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Rus_ich [418]
3 years ago
9

Question 4: In the fourth quadrant, the point will be in the form

Mathematics
2 answers:
Kisachek [45]3 years ago
7 0

Answer:

(+,-)

Step-by-step explanation:

quadrant 1 is (+,+)

quadrant 2 is (-,+)

quadrant 3 is (-,-)

quadrant 4 is (+.-)

Nata [24]3 years ago
5 0
Quadrant 4 is (+, -)
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Solve for x in the following inequality.<br><br> 4 - 3x ≤ 2x + 6
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(-2,5)

Step-by-step explanation:

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Customers of a phone company can choose between two servers plans for a long-distance calls. The first plant has $27 monthly fee
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First, you set up your equation then you put the pieces together to get the answer

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5 divide 15x 15squared
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75

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Emma borrowed $312 from her sister. She determines that she can pay her back in thirteen months worth of allowance. What effect
gulaghasi [49]

Answer:

This repayment will ultimately reduce her monthly bank account balance

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7 0
3 years ago
How do you factor 125-x^3?
xz_007 [3.2K]

Step-by-step explanation:

We have

125 - x {}^{3}

First, 125 is a perfect cube because

5 \times 5 \times 5 = 125

and

x^3 is a perfect cube because

x \times  x \times x = x {}^{3}

so we can use the difference of cubes identity

( {x}^{3}  -  {y}^{3} ) = (x - y)( {x}^{2}  + xy +  {y}^{2} )

Let say we have two perfect cubes:

64 because 8×8×8=64

and 27 because 3×3×3=27 and let subtract

64 - 27

we know that

64 - 27 = 37

but using the difference of cubes identity we should get the same thing.

Remeber cube root of 64 is 4 and cube root of 27 is 3 so we have

(4 - 3)( {4}^{2}  + 4(3) + 3 {}^{2} )

1(16 + 12 + 9) = 1(37) = 37

So the difference of cubes works for real numbers. This is a good way to help remeber the identity using real numbers.

Back on to the topic,

we know that 5 is cube root of 125 and x is the cube root of x^3 so we have

(5 - x)( {5}^{2}  + 5x +  {x}^{2} ) =

(5 - x)(25 + 5x +  {x}^{2} )

3 0
3 years ago
Read 2 more answers
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