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Sonbull [250]
3 years ago
9

Could anyone help me find the median???

Mathematics
2 answers:
inna [77]3 years ago
5 0
The median would be 0.14 ❤️❤️
Evgesh-ka [11]3 years ago
4 0

Answer:

0.14

Step-by-step explanation:

also if you dont mind giving me brainliest im trying to rank up, im 1 away. only if u dont mind

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The width of a rectangle is 4 meters less than twice the length. The area is 96 square meters. Find dimensions
stiv31 [10]

Answer:

Step-by-step explanation:

The width of a rectangle is 4 meters less than twice the length. The area is 96 square meters. Find dimensions

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I've been working on the same 5 questions for 3 hours and i give up im doing anything i can at this point​
zaharov [31]

Step-by-step explanation:

v = \pi \times r {}^{2}  \times h \div 3 \\  = \pi \times 2 {}^{2}  \times 10 \div 3 \\  = 41.8

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3 years ago
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What is the slope of the line that passes through the pair of points? (4.7).(7,-2)
Tju [1.3M]

Answer:

-3      i hope this helps :)

Step-by-step explanation:

(4,7)    (7,-2)

x1 y1    x2 y2

<u>-2 - 7 </u> = <u>-9</u> = -3

7  - 4      3

5 0
3 years ago
Find the value of x. Give your answer in simplest radical form.
yarga [219]
Using the pythagoras theorem for a right-angled triangle:-

x^2  = 13*2 - 9^2 = 88

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8 0
3 years ago
Marty's Barber Shop has one barber. Customers have an arrival rate of 2.2 customers per hour, and haircuts are given with a serv
Aleks [24]

Answer:

Step-by-step explanation:

Arrival rate = ∧ = 2.2 customers per hour

Service rate = u = 5 customers per hour

1. Probability that one customer is receiving a haircut and one customer is waiting

P(2 customers)=(∧/u)^2 * (1-∧/u)=(2.2/5)^2 * (1-2.2/5)=0.1936*0.56= 0.108416

2. Probability that one customer is receiving a haircut and two customers are waiting

P(3 customers)= (∧/u)^3 * (1-∧/u)=(2.2/5)^3 * (1-2.2/5)= 0.085184

* 0.56= 0.04770304

3. Probability that more than two customers are waiting

P(more than 3 customers)=1- P(less than 3 customers) =

1- [P(0)+P(1)+P(2)+P(3)]=

= 1- [(1-2.2/5) +2.2/5*(1- 2.2/5) + 0.108416+0.04770304]=1-0.9625=0.0375

3. Probability that more than two customers are waiting =

7 0
3 years ago
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