A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
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Answer:
0
Step-by-step explanation:
∫ sin²(x) cos(x) dx
If u = sin(x), then du = cos(x) dx.
∫ u² du
⅓ u³ + C
⅓ sin³(x) + C
Evaluate between x=0 and x=π.
⅓ sin³(π) − ⅓ sin³(0)
0
Answer:
Step-by-step explanation:
a = 5
r = -5
n = 9
t_9 = a r^(n - 1)
t_9 = (-1)^n*5 (-5) ^ 8
t_9 = (-1)^9 * 5 * (-5) ^8
t_9 = -1 ( 1953125)
t_9 = - 1953125
Answer:
Josie because 25 miles in 5 hours is 5 miles every hour and Greta runs 4.5 miles evry hour
Step-by-step explanation:
Answer:
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