Answer:
It does not hit the students face because the speed of the balloon slows down as energy is lost through thermal.
Explanation:
Answer:

Explanation:
<u>Motion with Constant Acceleration</u>
A body moves with constant acceleration when the speed changes uniformly in time. The equation used to find the final speed vf is

Where vo is the initial speed, a is the acceleration, and t is the time.
The cyclist has an initial speed of vo=10 miles/hour and ends up at vf=20 miles/hour in t=5 seconds.
Both speeds are given in miles/hour and we must convert it to m/s:
1 mile/hour = 0.44704 m/s
10 mile/hour = 4.47 m/s
20 mile/hour = 8.94 m/s
The acceleration is calculated by solving for a:



In several of the questions you've posted during the past day, we've already said that a wave with larger amplitude carries more energy. That idea is easy to apply to this question.
The car's final speed in m/s after the acceleration is 30.
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<u>Given the following data:</u>
- Initial velocity, U = 0 m/s (since the cars starts from rest)
- Acceleration, a = 3 meter per seconds square.
To find the car's final speed in m/s after the acceleration, we would use the first equation of motion;
Mathematically, the first equation of motion is given by the formula;

<em>Final speed, V </em><em>=</em><em> 30 m/s</em>
Therefore, the car's final speed in m/s after the acceleration is 30.
Read more: brainly.com/question/8898885
Answer:

Where
represent the force for each of the 5 cases
presented on the figure attached.
Explanation:
For this case the figure attached shows the illustration for the problem
We have an inverse square law with distance for the force, so then the force of gravity between Earth and the spaceship is lower when the spaceship is far away from Earth.
Th formula is given by:

Where G is a constant 
represent the mass for the earth
represent the mass for the spaceship
represent the radius between the earth and the spaceship
For this reason when the distance between the Earth and the Spaceship increases the Force of gravity needs to decrease since are inversely proportional the force and the radius, and for the other case when the Earth and the spaceship are near then the radius decrease and the Force increase.
Based on this case we can create the following rank:

Where
represent the force for each of the 5 cases
presented on the figure attached.