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Svetlanka [38]
3 years ago
13

A solenoid 2.5 cm in diameter and 30 cm in length has 4800 turns and carries a current of 2.0 A. Part A Calculate the magnetic f

lux through the circular cross-sectional area of the solenoid. Hint: Assume this is a very long solenoid and use the simplified magnetic field formula for an infinite solenoid.

Physics
1 answer:
IceJOKER [234]3 years ago
4 0

Answer: Ø = 0.034Wb

Explanation:

A solenoid is idealized as a certain number of current loops of diameter d in series.

• The current loops create a magnetic field. This field permeates each loop, ie, there is magnetic flux through each loop.

Determine the number of turns from the length and given winding rate.

• Calculate the strength of the magnetic field produced by the solenoid, then the flux through one turn (winding).

Please find the attached file for the solution.

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2 years ago
The heater element of a particular 120-V toaster is a 8.9-m length of nichrome wire, whose diameter is 0.86 mm. The resistivity
AleksAgata [21]

Answer:

Power, P = 722.96 watts

Explanation:

It is given that,

Voltage, V = 120 V

Length of nichrome wire, l = 8.9 m

Diameter of wire, d = 0.86 mm

Radius of wire, r = 0.43 mm = 0.00043 m

Resistivity of wire, \rho=1.3\times 10^{-6}\ \Omega-m

We need to find the power drawn by this heater. Power is given by :

P=\dfrac{V^2}{R}

And, R=\rho\dfrac{l}{A}

P=\dfrac{V^2\times A}{\rho\times l}

P=\dfrac{120^2\times \pi (0.00043)^2}{1.3\times 10^{-6}\times 8.9}

P = 722.96 watts

So, the power drawn by this heater element is 722.96 watts. Hence, this is the required solution.    

3 0
3 years ago
Physics/Math
Korolek [52]

Answer:

f = pl / (l + p)

Explanation:

1/f = 1/p + 1/l

Find the common denominator of the right hand side.

1/f = l/(pl) + p/(pl)

Add:

1/f = (l + p) / (pl)

Take the inverse of both sides:

f = pl / (l + p)

6 0
3 years ago
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