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Svetlanka [38]
3 years ago
13

A solenoid 2.5 cm in diameter and 30 cm in length has 4800 turns and carries a current of 2.0 A. Part A Calculate the magnetic f

lux through the circular cross-sectional area of the solenoid. Hint: Assume this is a very long solenoid and use the simplified magnetic field formula for an infinite solenoid.

Physics
1 answer:
IceJOKER [234]3 years ago
4 0

Answer: Ø = 0.034Wb

Explanation:

A solenoid is idealized as a certain number of current loops of diameter d in series.

• The current loops create a magnetic field. This field permeates each loop, ie, there is magnetic flux through each loop.

Determine the number of turns from the length and given winding rate.

• Calculate the strength of the magnetic field produced by the solenoid, then the flux through one turn (winding).

Please find the attached file for the solution.

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Home Business Cottage and Small Industries Development Committee to organize National Industrial Goods and...

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Cottage and Small Industries Development Committee to organize National Industrial Goods and Technology Expo

By Glocal Khabar - 2368 0

National Industrial Goods and Technology Expo- Glocal Khabar

Kathmandu, February 19, 2018: Cottage and Small Industries Development Committee is set to organize the twenty-ninth edition of National Industrial Goods and Technology Expo from March 23, 2018 at Bhrikutimandap, Kathmandu.

The motto of the five-day event is ‘Let’s use home-made products, move ahead towards prosperity.’ The committee has shared that handicrafts, wool and bamboo products, goods made from handmade papers, different types of pickles and Palpali Dhaka would be put on display in the expo.

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