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Svetlanka [38]
3 years ago
13

A solenoid 2.5 cm in diameter and 30 cm in length has 4800 turns and carries a current of 2.0 A. Part A Calculate the magnetic f

lux through the circular cross-sectional area of the solenoid. Hint: Assume this is a very long solenoid and use the simplified magnetic field formula for an infinite solenoid.

Physics
1 answer:
IceJOKER [234]3 years ago
4 0

Answer: Ø = 0.034Wb

Explanation:

A solenoid is idealized as a certain number of current loops of diameter d in series.

• The current loops create a magnetic field. This field permeates each loop, ie, there is magnetic flux through each loop.

Determine the number of turns from the length and given winding rate.

• Calculate the strength of the magnetic field produced by the solenoid, then the flux through one turn (winding).

Please find the attached file for the solution.

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Suppose that you make a series RC circuit with a capacitor and a known resistor that has a 5% tolerance: R= 5.20 ± 0.26kΩ. You p
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Answer:

correct answer is C

Explanation:

The time constant of an RC circuit is

           τ = RC

so to find the capacitance

          C = τ/ R

          C = 2.150 / 5.20 10³

          C = 4.13 10⁻⁴ F

to find the error we use the worst case

         ΔC = | |\frac{dC}{d \tau }| \ \Delta  \tau + | \frac{dC}{dR} | \ \Delta R

the absolute value guarantees that we find the worst case, we evaluate the derivatives

          ΔC = 1 /R Δτ + τ/R²  ΔR

the absolute values ​​of the errors are

          Δτ = 0.002 s

          ΔR = 0.3 kΩ

we substitute

           ΔC = 0.002 /5.20 10³ + 2.150/(5.20 10³)²   0.3 10³

           ΔC = 3.8 10⁻⁷ + 1.74 10⁻⁵

           ΔC = 1.77 10⁻⁵ F

the uncertainty or error must be expressed with a significant figure

            ΔC = 2 10⁻⁵ F

the percentage error is

            Er% =\frac{\Delta C}{C} \ 100

            Er% = \frac{2 \ 10^{-5} }{ 4.13 \ 10^{-4} } \ 100

            Er% = 4.8%

the correct answer is C

3 0
3 years ago
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