Question

Gravitational potential energy (Eg) and kinetic energy (Ek)

Answer 1

Answer:

hope it will help you

Explanation:

Answer 2

Answer:

$\boxed {\boxed {\sf E_K= \ 5,040 \ J}}$

Explanation:

Kinetic energy is the energy an object possesses due to motion. It is calculated using the following formula:

$E_K= \frac{1}{2} mv^2$

The mass of the athlete is 70.0 kilograms. The velocity is 12 meters per second.

• m= 70.0 kg
• v= 12 m/s

Substitute the values into the formula.

$E_K= \frac{1}{2} (70.0 \ kg)(12 \ m/s)^2$

Solve the exponent.

• (12 m/s)² = (12 m/s)(12 m/s) = 144 m²/s²

$E_K= \frac{1}{2} (70.0 \ kg)(144 \ m^2/s^2)$

Multiply the numbers together.

$E_K= \frac{1}{2} (10, 080 \ kg*m^2/s^2)$

$E_K= 5,040 \ kg*m^2/s^2$

Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule, so our answer is equal to 5,040 Joules.

$E_K= 5.040 \ J$

The athlete has 5,040 Joules of kinetic energy.