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Free_Kalibri [48]
3 years ago
11

Please answer ASAP,

Chemistry
1 answer:
andrew11 [14]3 years ago
6 0

Answer:

B

Explanation:

I took the test and GOT an A

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In what orbital would to valence electrons of strontium be found? a.) 5s b.) 4s c.) none d.) 5p​
KonstantinChe [14]

Answer:

The correct answer is 5s

Explanation:

Strontium atomic number = 38

Electronic configuration is $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 5s^{2}

As $5s$ orbital is valence orbital in strontium, the outer electrons exists in that orbital only.

4 0
3 years ago
In which way are a prokaryotic cell and a eukaryotic cell alike?  
inessss [21]
Prokaryotic cells do not contain membrane-closed organelles, (??) and they are not the same size at all. (prokaryotic are way smaller) Just to help narrow down, if I'm right! (: Sorry, I know that's not completely helpful.
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3 years ago
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What is the conjugate base of ch3ch2co2h?
Novay_Z [31]
The conjugate base of ch3ch2co2h or propanoic acid would be CH3CH2COO- or propanoate. The conjugate base is what is left after an acid has donated a proton in a reaction. Hope this answers the question. Have a nice day.
3 0
3 years ago
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Calcium Carbonate decomposes at 1200°C to form carbon dioxide and
Travka [436]

This is a Charles' Law problem: V1/T1 = V2/T2. As the temperature of a fixed mass of gas decreases at a constant pressure, the volume of the gas should also decrease proportionally.

To use Charles' Law, the temperature must be in Kelvin (x °C = x + 273.15 K). We want to solve Charles' Law for V2, which we can obtain by rearranging the equation into V2 = V1T2/T1. Given V1 = 25 L, T1 = 1200 °C (1473.15 K), and T2 = 25 °C (298.15 K):

V2 = (25 L)(298.15 K)/(1473.15 K) = 5.1 L.  

5 0
3 years ago
How many mililiters of a 6 00 M NaOH solution are needed to provide 0 330 mol of NaOH?​
Bumek [7]

Answer:

55mL of sodium hydroxide are required.

Explanation:

Given data:

Molarity of NaOH solution = 6.00 M

Number of moles of NaOH = 0.330

Volume required = ?

Solution:

Formula:

M = n/v

M = molarity

n = number of moles

v = volume

Now we will put the values in formula.

6.00 M = 0.330 mol / v

v = 0.330 mol / 6.00 M

v = 0.055 L  (M = mol/L)

v = 0.055 L × 1000 mL/ 1L

v = 55 mL

55mL of sodium hydroxide are required.

4 0
3 years ago
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