If 6.89 g of CuNO3 is dissolved in water to make a 0.460 M solution, what is the volume of the solution?

Chemistry

1 answer:

Readme [11.4K]4 years ago

6 0

3.67 grams is the volume of the solution

You might be interested in

If 5.55 moles of gas have a volume of 12.2 L, what is the new volume when the moles of

KatRina [158]

Answer:

$12.61 + 5.55) \div 12.2 =$

Explanation:

it's too easy

8 0

2 years ago

When lewis structures are drawn, do you only show valence electrons??

Lynna [10]

Yes you do cause its more explanation to
<span />

8 0

3 years ago

If temperature is increased , the number of collisions per second

AfilCa [17]

Answer: when the temperature is increased, the number of collisions per second increases.

Explanation:

the rate of collisions and the temperature is directly proportional. If the energy of the gas particles is boosted by using the temperature, the chances of the particles bumping into each other due to the high energy increases, thus increasing the number of collisions. This also increases the rate of reaction. Thus when temperature is increased the number of collisions also increases.

4 0

3 years ago

Electron transfer is the term for this process. The resulting anion and cation are attracted by Coulombic forces and an ionic co

Nitella [24]

<h2>The compound formed is NaCl and $CaCl_{2}$ </h2>

Explanation:

PART 1:

Atomic number of sodium is 11.
Sodium(Na, Z = 11, Group 1A) will lose 1 electron to become $Na^{1+}$ which is isoelectronic to Neon (Ne ,Z = 10).
The symbol for the sodium ion is $Na^{+}$ .
Chlorine atom ( $Cl$ , Z = 17, Group 7A or 17) gains 1 elecron to be isoelectronic to neon.
The symbol for the compound formed is NaCl.
PART 2:
Atomic number of calcium is 20
Calcium(Ca, Z = 20 ,Group 2A) will lose two electrons to become $Ca^{2+}$ which is isoelectronic to argon.
The symbol for the ion is $Ca^{2+}.$
Two chlorine atoms (Cl, Z = 17, Group 7A or 17) each gains one electron to be isoelectronic to argon(Z = 18)
The symbol for the compound formed is $CaCl_{2}$ .