Al2(SO4)3 + 3CaCl2 > 2AlCl3 + 3CaSO4
The Arrhenius equation relates activation energy to reaction rates and temperature:
ln (k2 / k1) = (E / R) * (1/T1 - 1/T2), where E is activation energy of 272 kJ, R is the ideal gas constant (we use the units of 0.0083145 kJ/mol-K for consistency, to cancel out the kJ unit), we let T1 = 718 K and k1 = 2.30 x 10^-5, and T2 = 753 K and k2 be the unknown.
ln (k2 / 2.30x10^-5) = (272 kJ / 0.0083145 kJ/mol-K) * (1/718 - 1/753)
k2 = 1.91 x 10^-4 /s
Answer:
The aromatic ringsare the number 1 and 2.
Identify which lone pairs are participating in resonance (in aromatic rings).
- One lone pair on the sulfur atom.
Explanation:
For a compound to be aromatic it has to comply with Hückel's Rule, which says that the quantity of electrons in the pi orbitals, has to be a multiple of
4n + 2
for n = 0, 1, 2, 3.
When 0.5 moles of Zn react with 0.4 moles of HCL the limiting reactant will be HCL and excess reactant is Zn 0.3 moles excess and 0.2 moles Zn will be consumed in the reaction.
<h3>What is the limiting reactant in the given equation ?</h3>
STEP1- Write the balanced equation
Zn + 2HCL → ZnCl₂ + H₂
STEP2- calculate the moles according to the reaction
1mol of Zn requires → 2moles of HCL
0.5 moles of Zn requires→ 1mol of HCL
Given moles of HCL is 0.4
STEP3- Apply unitary method
0.5/x=1/0.4
0.5×0.4= x
0.2=x
STEP4- excess reagent left 0.5-0.2=0.3
Hence, the 0.3mole of excess Zn is left
Learn more about limiting reactions numericals.
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