Answer:
A solution in which no more solute can be dissolved in is referred to as SATURATED. In such a solution, the concentration of solute is called SOLUBILITY . When that concentration is reported in moles per liter, it is more specifically called MOLAR SOLUBILITY. A special equilibrium constant called the SOLUBILITY PRODUCT constant is calculated from the molar concentrations of the aqueous components of the dissolution equation.
Explanation:
The solubility of a solute in a solvent is the maximum amount of solute in moles that will be dissolved in 1dm3 of the solvent at a specified temperature. Once the maximum number or concentration has been reached, the solvent can no longer take in solutes and this point in the reaction, the solution is said to be saturated. That is the composition of the saturated solution is not affected by the presence of excess solute. An unsaturated solution has a lower concentration of solute and can dissolve more solutes if added until it becomes saturated.
Solubility when reported in moles per liter is called molar solubility of the solution and it gives a more accurate measurement of yh solubility of a solution. The solubility product constant is calculated from the molar concentrations of the aqueous components of the dissolution equation. This solubility product constant explains the balance between dissolved ions from the salt and undissolved salt in a dissolution equation.
To calculate the pH of a solution that has a [H3O+] of 7.22x10^-7. You would do the following
pH=-log[H3O+]
pH=-log[7.22x10^-7]
pH=?
I think it's calorie
Hope this helps
Protons are bound together by strong nuclear force .
Hope this helps (:
Answer:
Explanation:
10 mL = .01 L .
25 mL = .025 mL .
10 mL of .1 M NaOH will contain .01 x .1 = .001 moles
25 mL of .1M HCl will contain .025 x .1 = .0025 moles
acid will neutralise and after neutralisation moles of acid remaining
= .0025 - .001 = .0015 moles .
Total volume = .01 + .025 = .035 L
concentration of remaining HCl = .0015 / .035
Option D is correct.
= .042857 M
= 42.857 x 10⁻³ M .
pH = - log [42.857 x 10⁻³]
= 3 - log 42.857
= 3 - 1.632
= 1.368 .
