Answer:
(12, "circle”, “square") is the correct answer.
Explanation:
The following answer is true because the following answer is in the correct format. The tuple is the data type of the Python Programming language which is defined inside the parentheses "()" and it is an immutable type that means its elements is not changed after once the element is inserted in the tuple. Tiple is also defined by the parentheses "()" or by the predefined function tuple().
Answer:
SELECT inventory_id, film_id, title, store_id, address_id
FROM Inventory.Inventory
JOIN Business.store ON Inventory.store_id = store.store_id
JOIN Business.rental ON rental.film_id = Inventory.film_id
JOIN film_text ON Inventory.film_id = film_text.film_id
WHERE COUNT(rental_id) = 0;
Explanation:
The JOIN clause is also used to query tables from two databases. The Inventory and the Business database are joined in the inventory and store table respectively. The Query also joins the inventory table and the film_text table to get the title or name of the film rented where the rental_id count is equal to zero.
They could find you and throw hands.
Answer:
Question is incomplete.
Assuming the below info to complete the question
You have a collection of n lockboxes and m gold keys. Each key unlocks at most one box. Without a matching key, the only way to open a box is to smash it with a hammer. Your baby brother has locked all your keys inside the boxes! Luckily, you know which keys (if any) are inside each box.
Detailed answer is written in explanation field.
Explanation:
We have to find the reachability using the directed graph G = (V, E)
In this V are boxes are considered to be non empty and it may contain key.
Edges E will have keys .
G will have directed edge b1b2 if in-case box b1 will have key to box b2 and box b1 contains one key in it.
Suppose if a key opens empty box or doesn’t contain useful key means can’t open anything , then it doesn’t belongs to any edge.
Now, If baby brother has chosen box B, then we have to estimate for other boxes reachability from B in Graph G.
If and only if all other boxes have directed path from box B then just by smashing box B we can get the key to box b1 till last box and we can unlock those.
After first search from B we can start marking all other vertex of graph G.
So algorithm will be O ( V +E ) = O (n+m) time.
