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KengaRu [80]
3 years ago
11

3. What three numbers are the Pythagorean triple generated by using 4 for x and 1 for y. Remember to use the formulas:

Mathematics
1 answer:
Doss [256]3 years ago
8 0

Given:

Consider the three number are given by:

a=x^2-y^2

b=2xy

c=x^2+y^2

To find:

The three numbers are the Pythagorean triple generated by using 4 for x and 1 for y.

Solution:

We have,

a=x^2-y^2

b=2xy

c=x^2+y^2

Substituting 4 for x and 1 for y, we get

a=4^2-1^2

a=16-1

a=15

Similarly,

b=2(4)(1)

b=8

And,

c=4^2+1^2

c=16+1

c=17

The three three numbers are the Pythagorean triple are 8,15 and 17.

Therefore, the correct option is C.

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A rectangle has a perimeter 60m and base21 m what is its area
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Since you're given the base for the perimeter of the rectangle, you can solve this question quickly.

First, you multiply 21 by 2, because there are two bases to a rectangle.

You'll get 42, and you will have to do 60-42 to find the perimeter for the remaining two sides.

60-42 will give you 18, so you can divide that by 2 because there are two other sides, giving you 9.

Now you have the side lengths 21 and 9. Area is base*height, so you can multiply 21*9 and get 189.

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What is the largest multiple of 36 that can be written with each digit 0-9 exactly once?
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Answer:

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Step-by-step explanation:

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svp [43]

Answer:

The American population was 20% of the British population.

Step-by-step explanation:

Let us call A the american population, B the British population before the migration, and x the population that migrated from America to Britannia.

Now, the population x that migrated was 20% of the american population:

(1).\: \: x = 0.2A,

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x+B = 1.04B \\\\ (2). \:\:x = 0.04B.

Combining equation (1) and (2) we get:

0.2A = 0.04B

A = \dfrac{0.04B}{0.2}

\boxed{A = 0.2B}

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Vitek1552 [10]
The mode of the values listed is 9.
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M is the centroid (center of gravity) of △ABC, line k goes thru M and intersects AB and AC . The distances of the vertices B and
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Answer:

  30

Step-by-step explanation:

The midpoint of BC will be a distance from line k that is the average of the distances of B and C: (17+13)/2 = 15. Call that midpoint P. We know distance MP is half of distance MA. This same relationship will hold with respect to the distances from P and A to any line through M. That is, the distance from line k (through M) is twice the distance from P to line k: 30 units.

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