All categories

2 years ago

The function h is defined by H(x)=x^2-6 find h(5x). H(5x)=

Mathematics

1 answer:

Stolb23 [73]2 years ago

3 0

$h(x)\ \ =\ x^2-6\\.\ \ \downarrow\ \ \ \ \ \ \ \ \downarrow\\h(5x)=(5x)^2-6=(5)^2(x)^2-6=25x^2-6$

You might be interested in

Help me please thanks

Afina-wow [57]

Innermost orbitals have the least amount of energy

4 0

2 years ago

Read 2 more answers

I don’t know how to set it up nor do it please help me

marusya05 [52]

Answer:

The value of x is 3

Step-by-step explanation:

∵ Quadrilateral ABCD is congruent to quadrilateral JKLM

∴ AB = JK and BC = KL

∴ CD = LM and AD = JM

∵ BC = 8x + 7

∵ KL = 31

∵ BC = KL

→ Equate their right sides

∴ 8x + 7 = 31

→ Subtract 7 from both sides

∵ 8x + 7 - 7 = 31 - 7

∴ 8x = 24

→ Divide both sides by 8 to find x

∴ $\frac{8x}{8}$ = $\frac{24}{8}$

∴ x = 3

∴ The value of x is 3

8 0

2 years ago

The water diet requires you to drink two cups of water every half hour from the time you get up until you go to bed, but otherwi

Elan Coil [88]

Answer:

$7-3.182 \frac{13.638}{\sqrt{4}}= -14.698$

$7+3.182 \frac{13.638}{\sqrt{4}}= 28.698$

Step-by-step explanation:

For this case we have the following info given:

Weight before diet 180 125 240 150

Weight after diet 170 130 215 152

We define the random variable $D = before-after$ and we can calculate the inidividual values:

D: 10, -5, 25, -2

And we can calculate the mean with this formula:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

And the deviation with:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}$

And after replace we got:

$\bar D= 7, s_d = 13.638$

And the confidence interval for this case would be given by:

$\bar D \pm t_{\alpha/2} \frac{s_d}{\sqrt{n}}$

The degrees of freedom are given by:

$df = n-1= 4-1=3$

For the 95% of confidence the value for the significance is $\alpha=0.05$ and the critical value would be $t_{\alpha/2}= 3.182$ . And replacing we got:

$7-3.182 \frac{13.638}{\sqrt{4}}= -14.698$

$7+3.182 \frac{13.638}{\sqrt{4}}= 28.698$

6 0

2 years ago

Two mixed numbers that have a sum of 3

hram777 [196]

1 1/2 + 1 1/2 & 1 3/4 + 1 1/4

6 0

2 years ago

1/2-3(1/2 +1 )^2

MAVERICK [17]

$\bf \cfrac{1}{2}-3\left( \cfrac{1}{2}+1 \right)^2\implies \stackrel{\mathbb{PEMDAS}}{\cfrac{1}{2}-3\left( \cfrac{1+2}{2} \right)^2}\implies \cfrac{1}{2}-3\left( \cfrac{3}{2} \right)^2 \\\\\\ \cfrac{1}{2}-3\left( \cfrac{3^2}{2^2} \right)\implies \cfrac{1}{2}-3\cdot \cfrac{9}{4}\implies \cfrac{1}{2}-\cfrac{27}{4}\implies \stackrel{\textit{LCD of 4}}{\cfrac{2-27}{4}} \\\\\\ -\cfrac{25}{4}\implies -6\frac{1}{4}$

4 0

2 years ago