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Inessa05 [86]
3 years ago
15

ASAP PLEASE HELP!!!! WRITE AN EXPRESSION

Mathematics
1 answer:
zysi [14]3 years ago
5 0

Answer:

10c + 5b + 420 + 4c

Step-by-step explanation: 10 dollars for each child, 5 dollars per a pair of rubber boots, party room is 420 and 4 is per each child's pizza

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The length of the rectangle is 2x + 8 cm and the width is 2cm . The area of the rectangle is 12 cm​
Ksju [112]

Answer:

x = - 1

Step-by-step explanation:

Length ( l ) = 2x + 8 cm

Width / Breadth ( b ) = 2 cm

Area ( rectangle ) = 12 cm

Formula : -

Area ( rectangle ) = lb

12 = ( 2x + 8 ) ( 2 )

Divide 2 on both sides,

12 / 2 = ( 2x + 8 ) ( 2 ) / 2

6 = 2x + 8

2x + 8 = 6

2x = 6 - 8

2x = - 2

x = - 2 / 2

x = - 1

5 0
3 years ago
Find the area of the region that is NOT shaded.
Mice21 [21]
If u think of it this way 
8*4=32 it has to be smaller than that so my best guess would be 
C) 20 square units
6 0
4 years ago
Read 2 more answers
A kite is designed on a rectangular grid with squares that measure 1cm by 1 cm. A hexagonal piece within the kite will be reserv
Nata [24]

Answer:

The answer is the first answer

P = 8 + 4√13 cm

A = 36 cm²

Step-by-step explanation:

* Lets study the figure

- Its a kite with two diagonals

- The shortest one is 12 cm

- The longest one is 26 ⇒ axis of symmetry of the kite

- the shortest diagonal divides the longest into two parts

- The smallest part is 8 cm and the largest one is 18 cm

* To find the area reserved for the logo divide

 the hexagonal piece into two congruent trapezium

- The length of the two parallel bases are 4 cm and 8 cm and

  its height is 3 cm

- The length of non-parallel bases can calculated by Pythagoras rule

∵ The lengths of the two perpendicular sides are 2 cm and 3 cm

- 3 cm is the height of the trapezium

- 2 cm its the difference between the 2 parallel bases ÷ 2

  (8 - 4)/2 = 4/2 = 2 cm

∴ The length of the non-parallel base = √(2² + 3²) = √13

* Now we can find the area of the space reserved for the logo

- The area of the trapezium = (1/2)(b1 + b2) × h

∴ The area = (1/2)(4 + 8) × 3 = (1/2)(12)(3) = 18 cm²

∵ The space reserved for the logo are 2 trapezium

∴ The area reserved for the logo = 2 × 18 = 36 cm²

* The area of the reserved space for the logo = 36 cm²

* The perimeter of the reserved space for the logo is the

  perimeter of the hexagon

∵ The lengths of the sides of the hexagon are:

   4 cm , 4 cm , √13 cm , √13 cm , √13 cm , √13 cm

∴ The perimeter = 2(4) + 4(√13) = 8 + 4√13 cm

* The perimeter of the reserved space for the logo = 8 + 4√13 cm

4 0
3 years ago
A store bought a sofa whole sale for 200
balandron [24]

Answer:

what is the question

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Write the vector u as a sum of two orthogonal vectors, one of which is the vector projection of u onto v, proj,u
11Alexandr11 [23.1K]

Answer:

Take b = \frac{-17}{25}(7,1) as the projection of u onto v and w \frac{1}{25}(-31,217) as the vector such that b+w =u

Step-by-step explanation:

The formula of projection  of a vector u onto a vector v is given by

\frac{u\cdot v}{v\cdot v}v, where cdot is the dot product between vectors.

First, let b ve the projection of u onto v. Then

b = \frac{u\cdot v}{v\cdot v}v= \frac{-6\cdot 7+8\cdot 1}{7\cdot 7+1\cdot 1}(7,1) = \frac{-34}{50}(7,1) = \frac{-17}{25}(7,1)

We want a vector w, that is orthogonal to b and that b+w = u. From this equation we have that w = u-b = (-6,8)-\frac{-17}{25}(7,1)= \frac{1}{25}(-31,217)[/tex]

By construction, we have that w+b=u. We need to check that they are orthogonal. To do so, the dot product between w and b must be zero. Recall that if we have vectors a,b  that are orthogonal then for every non-zero escalar r,k the vector ra and kb are also orthogonal. Then, we can check if w and b are orthogonal by checking if the vectors (7,1) and (-31, 217) are orthogonal.

We have that (7,1)\cdot(-31,217) = 7\cdot -31 + 217 \cdot 1 = -217+217 =0. Then this vectors are orthogonal, and thus, w and b are orthogonal.

5 0
3 years ago
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