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3 years ago

Find the correct plugged in formula for each figure.

Mathematics

2 answers:

Vladimir [108]3 years ago

5 0

The awnser to this problem is like 1007

ella [17]3 years ago

5 0

1,007 is the answer

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PLEASE HELP QUICK ITS TIMED

juin [17]

Answer:

Step-by-step explanation:

I think what they are asking is to subtract the 3 tokens from 21 tokens he already has giving us 18. and since it says "Twice the number of tokens" I'm assuming you divide 2 from 18 giving you 9 tokens.

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3 years ago

Find the common difference for the given sequence.

Lyrx [107]

The answer is you add 0.05 every time

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3 years ago

32 is 10 increased by a number

Anastaziya [24]

i dont understand the question?

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4 years ago

4 The ratio of corresponding dimensions of two similar solids is 3/4. The surface

White raven [17]

4.

The ratio is 3/4 for corresponding dimensions, the ratio of their surface areas is equal to the square of this ratio:

$\sf (\dfrac{3}{4})^2=\dfrac{S}{96}$

Simplify the exponent:

$\sf \dfrac{9}{16}=\dfrac{96}{S}$

Cross multiply:

$\sf 9S=1536$

Divide 9 to both sides:

$\sf S\approx 170.7~m^2$

So the surface area of the second solid is 54 square meters.

The ratio is 3/4 for corresponding dimensions, the ratio of their volumes is equal to the cube of this ratio:

$\sf (\dfrac{3}{4})^3=\dfrac{720}{V}$

Simplify the exponent:

$\sf \dfrac{27}{64}=\dfrac{720}{V}$

Cross multiply:

$\sf 27V=46080$

Divide 64 to both sides:

$\sf V\approx 1706.7~m^3$

5.

A globe is a sphere, use the formula for the volume of a sphere:

$\sf V=\dfrac{4}{3}\pi r^3$

The radius is half of the diameter, so the radius here is 40/2 = 20. Plug it in the formula, use 3.14 to approximate for Pi:

$\sf V=\dfrac{4}{3}(3.14)(20)^3$

Simplify the exponent:

$\sf V=\dfrac{4}{3}(3.14)(8000)$

Multiply:

$\sf V\approx \boxed{\sf 33,493~in^3}$

6 0

4 years ago

Read 2 more answers

Identify the reason that justifies the statement.

Amiraneli [1.4K]

Answer:

C; Substitution property

Step-by-step explanation:

Here, we want to find the justification that justifies the written equation;

If PQ + RS = PS

and RS = XY

then PQ + XY = PS

What we simply did is to substitute RS for XY in the second equation;

The correct answer is Substitution property

It can be fully referred to as the substitution property of equality.

What it simply means in a nut shell is that since XY and RS are equal, then in any addition or arithmetic equation, we can make a substitution of XY for RS since they are equal to each other

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3 years ago