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3 years ago

9

PLEASE HELP!! which graph represents the function f(x) = -|x| - 2

1 answer:

Nonamiya [84]3 years ago

4 0

Answer:

The graph on the far right

Step-by-step explanation:

The negative in front of the absolute value indicates that the parent function |x| has been reflected over the x-axis and points downwards. The negative 2 being added to this portion shows that there has been a vertical shift of two units downwards as well. Therefore, the graph on the far right is the correct graph.

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4 years ago

1-Suppose the path of a baseball follows the path graphed by the quadratic function ƒ(d) = –0.6d2 + 5.4d + 0.8 where d is the ho

jasenka [17]

Answer:

1. The correct option B.

2.The correct option A.

Step-by-step explanation:

The given function is

$f(d)=-0.6d^2+5.4d+0.8$

Where f(d) is the height of the ball at horizontal distance d.

Put f(d)=0, to find the distance where the ball touch the ground.

$0=-0.6d^2+5.4d+0.8$

Quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Using the quadratic formula we get

$d=\frac{-5.4\pm \sqrt{(5.4)^2-4(-0.6)(0.8)}}{2(-0.6)}$

$d=-0.146,9.146$

Therefore the ball is in air between d=-0.146 to d=9.146.

The distance can not be negative, therefore the ball remains in the air between d=0 to d=9.146.

$9.146\approx 9.15$

Therefore the correct option is B.

2.

The given equation is

$y=(x-1)^2+1$ .... (1)

The standard form of parabola is

$y=a(x-h)^2+h$ .... (2)

Where, a is constant and (h,k) is vertex.

On comparing (1) and (2), we get

$a=1$

$h=1$

$k=1$

Since the value of a is positive, therefore it is an upward parabola. The vertex of the parabola is (1,1).

Put x=0 in the given equation.

$y=(0-1)^2+1$

$y=1+1=2$

Therefore the y-intercept is (0,2) and option A is correct.

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