Answer: Option E is the correct answer; (1 + p⁴) / (1 + p³)
Step-by-step explanation:
P (3 head) = P(first and 3 heads) + P(second coin and 3 heads)
= (1/2)×1³ + (1/2)× p³ = (1/2) × (1 + p³)
therefore P(first coin given 3 heads) = (1/2)×1³/ ((1/2)×(1 + p³))
= 1 / (1 + p³)
Also P( second coin given 3 heads) = p³ /(1 + p³)
therefore P(4th toss in heads given first 3 are heads) will be;
= P(first and 4th toss heads) + P(second and 4th toss heads)
=(1/( 1 + p³ )) × 1 + p³ / (1+p³) × p
= (1 + p⁴) / (1 + p³)
Therefore Option E is the correct answer
Answer:
Step-by-step explanation:
I will solve this question with the attached triangle
From the attachment, we have:
Required
Solve the triangle
First, we calculate 
using sine law:
This gives:
Cross multiply
Divide both sides by 29
Take arcsin of both sides
Next, calculate 
using:
--- angles in a triangle
Collect like terms
Next, calculate BC using sine laws
This gives:
Make BC the subject
The algebraic property demonstrated in the example below is Transitive Property of Equality. There we can see how the first thing is equal to the second one and notice that the first one is equal to the third one too. This is a Transitive Property of Equality in a nutshel.
The answer is D. -15 because I am assuming that the vertical lines mean brackets, and we have to work out the brackets first (according to BIDMAS). Doing so, -6 + 2 = -4 and -4 + -11 = -15.
1+(put the little sign)6
that should be the answer, good luck.
