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valentina_108 [34]
3 years ago
6

Which expression is equivalent to 4 (3n - 5)?

Mathematics
1 answer:
Fynjy0 [20]3 years ago
4 0
12n - 20 is the answer
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What is the radius of the circle given the equation x2 - 6x + y2 + 10y - 2 = 0?
Bezzdna [24]
4x+12y=2
2=4x+12y
2x+6y
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Please help me I’ll give you a thanks :-)
Sonbull [250]

Answer:

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The ans is in the picture with the  steps how i got it

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Step-by-step explanation:

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3 years ago
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The cost to attend a Wildcat sports event is: Adult: $7 Student: $5 The total sales was $700.
hram777 [196]

Answer:

7x+5y=700

91 student tickets

Step-by-step explanation:

7x+5y=700

7(35)+5y=700

245+5y=700

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4 0
3 years ago
7w-180=52w what does w equal
BartSMP [9]

Answer: w= -4

Step-by-step explanation:

7w-180=52w

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4 0
4 years ago
What is the square root of m^6?
Nastasia [14]
Answer:
If m is nonnegative (ie not allowed to be negative), then the answer is m^3
If m is allowed to be negative, then the answer is either |m^3| or |m|^3

==============================

Explanation:

There are two ways to get this answer. The quickest is to simply divide the exponent 6 by 2 to get 6/2 = 3. This value of 3 is the final exponent over the base m. Why do we divide by 2? Because the square root is the same as having an exponent of 1/2 = 0.5, so
sqrt(m^6) = (m^6)^(1/2) = m^(6*1/2) = m^(6/2) = m^3
This assumes that m is nonnegative. 

---------------------------

A slightly longer method is to break up the square root into factors of m^2 each and then apply the rule that sqrt(x^2) = x, where x is nonnegative

sqrt(m^6) = sqrt(m^2*m^2*m^2)
sqrt(m^6) = sqrt(m^2)*sqrt(m^2)*sqrt(m^2)
sqrt(m^6) = m*m*m
sqrt(m^6) = m^3
where m is nonnegative

------------------------------

If we allow m to be negative, then the final result would be either |m^3| or |m|^3. 

The reason for the absolute value is to ensure that the expression m^3 is nonnegative. Keep in mind that m^6 is always nonnegative, so sqrt(m^6) is also always nonnegative. In order for sqrt(m^6) = m^3 to be true, the right side must be nonnegative.

Example: Let's say m = -2
m^6 = (-2)^6 = 64
sqrt(m^6) = sqrt(64) = 8
m^3 = (-2)^3 = -8
Without the absolute value, sqrt(m^6) = m^3 is false when m = -2

4 0
3 years ago
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