So if John gives a pen and pencil to each and all of them are over we know that the no. of pencils and pens should be the same
So we will find the LCM of 15 and 40 that is equal to 120
So John brought 120/15 that is 8 packets of pen and 120/40 that is three packets of pencils
Sure let’s see.... I believe it is D, but I’m not 100%. Don’t give low ratings. I tried.
Answer:
H
Step-by-step explanation:
Step 1 of 2: Subtract, sub-step b: Convert mixed number to improper fraction.
Convert mixed number to improper fraction
2 and 1 over 32
1
3
= ( 2 × 3 ) over 3
2 × 3
3
+ 1 over 3
1
3
= ( 6 + 1 ) over 3
6 + 1
3
= 7 over 3
7
3
Step 1 of 2: Subtract, sub-step c: Find common denominator.
Find common denominator
32 over 9
32
9
− 7 over 3
7
3
= ( 32 × 1 ) over ( 9 × 1 )
32 × 1
9 × 1
− ( 7 × 3 ) over ( 3 × 3 )
7 × 3
3 × 3
= 32 over 9
32
9
− 21 over 9
21
9
9 is the least common multiple of denominators 9 and 3. Use it to convert to equivalent fractions with this common denominator.
Step 1 of 2: Subtract, sub-step d: Subtract.
Subtract
32 over 9
32
9
− 21 over 9
21
9
= ( 32 − 21 ) over 9
32 − 21
9
= 11 over 9
11
9
Step 1 of 2: Subtract.
Step 2 of 2: Simplify.
Simplify
11 over 9
11
9
= 1 and 2 over 91
2
9
Answer:
(i) 22.5
(ii) 7.2
Step-by-step explanation:
(i)
AB:PQ = 2:5 = 1:2.5
So PQ is 2.5 times longer than AB.
PQ=2.5AB=(2.5)9=22.5
(ii):
Since the triangles are similar, their sides are in ratio to each other. So if PQ was 2.5 times longer than AB, QR must also be 2.5 times longer than BC:
QR=2.5BC
BC=QR/2.5=18/2.5=7.2
Answer:
-5 and -10
Step-by-step explanation:
