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vichka [17]
3 years ago
6

A school bus moves down a road, dropping off students after school. The bus slows down from a speed of 15 meters per second to a

full stop over a distance of 55 meters in 11 seconds. What is the average speed, in meters per second, of the school bus while the bus is slowing down? * 3.7 5.0 26 40
Physics
1 answer:
My name is Ann [436]3 years ago
5 0

Given :

A school bus moves down a road, dropping off students after school.

The bus slows down from a speed of 15 meters per second to a full stop over a distance of 55 meters in 11 seconds.

To Find :

The average speed, in meters per second, of the school bus while the bus is slowing down.

Solution :

Initial velocity, u = 15 m/s.

Distance travelled, d = 55 m.

Time taken, t = 11 s.

Final velocity, v = 0 m/s.

We know, average velocity is given by :

v_{avg}=\dfrac{distance}{time}\\\\v_{avg}= \dfrac{55}{11}\ m/s\\\\v_{avg}=5 \ m/s

Therefore, average velocity is 5 m/s.

Hence, this is the required solution.

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A 1300 kg car traveling with a speed of 3.5 m/s executes a turn with a 8.5 m radius of curvature.
Y_Kistochka [10]

Answer:

1.4 m/s/s (2.s.f)

Explanation:

The formula for centripetal acceleration is:

a=\frac{v^{2} }{r}, where v is velocity and r is the radius.

In the question we are given the information that the car has a mass of 1300kg, a velocity of 2.5m/s, and a turn radius of 8.5m which are all the values we need. Therefore we can simply substitute in the values to solve the question:

a=\frac{3.5^{2} }{8.5} \\a=1.4

Therefore the centripetal acceleration of the car is 1.4m/s/s. (2.s.f)

Hope this helped!

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3 years ago
Delivery trucks that operate by making use of energy stored in a rotating flywheel have been used in Europe. The trucks are char
Marta_Voda [28]

Answer:

KE = 2.535 x 10⁷ Joules

Explanation:

given,

angular speed of the fly wheel = 940 rad/s

mass of the cylinder = 630 Kg

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KE of flywheel = ?

moment of inertia of the cylinder

I = \dfrac{1}{2}mr^2

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 = 574 kg m²

kinetic energy of the fly wheel

KE = \dfrac{1}{2}I\omega^2

KE =\dfrac{1}{2}\times 574\times 940^2

KE = 2.535 x 10⁷ Joules

the kinetic energy of the flywheel is equal to KE = 2.535 x 10⁷ Joules

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