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vichka [17]
3 years ago
6

A school bus moves down a road, dropping off students after school. The bus slows down from a speed of 15 meters per second to a

full stop over a distance of 55 meters in 11 seconds. What is the average speed, in meters per second, of the school bus while the bus is slowing down? * 3.7 5.0 26 40
Physics
1 answer:
My name is Ann [436]3 years ago
5 0

Given :

A school bus moves down a road, dropping off students after school.

The bus slows down from a speed of 15 meters per second to a full stop over a distance of 55 meters in 11 seconds.

To Find :

The average speed, in meters per second, of the school bus while the bus is slowing down.

Solution :

Initial velocity, u = 15 m/s.

Distance travelled, d = 55 m.

Time taken, t = 11 s.

Final velocity, v = 0 m/s.

We know, average velocity is given by :

v_{avg}=\dfrac{distance}{time}\\\\v_{avg}= \dfrac{55}{11}\ m/s\\\\v_{avg}=5 \ m/s

Therefore, average velocity is 5 m/s.

Hence, this is the required solution.

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(a)
Marta_Voda [28]

a) The momentum of the coconut is 3 kg m/s

b) At first, the air resistance is negligible, so the coconut accelerates due to the force of gravity

c) The coconut reaches its terminal velocity

Explanation:

a)

The momentum of an object is given by the equation

p=mv

where

m is the mass of the object

v is its velocity

For the coconut in this problem, we have:

m = 1.5 kg (mass)

v = 2 m/s (velocity)

Therefore, its momentum is

p=(1.5)(2)=3 kg m/s

B)

There are only two forces acting on the coconut during its fall:

  • The force of gravity, of magnitude mg (m= mass of the coconut, g = acceleration of gravity), acting downward
  • The air resistance, acting upward, whose magnitude is proportional to the speed of the coconut

During the first momentums of the fall, the speed of the coconut is still low, so the air resistance is mostly negligible, and therefore only the force of gravity is acting on the coconut. Since this force is constant, it means that the acceleration of the coconut is constant: therefore, its velocity keeps increasing during the fall, and the coconut speeds up.

C)

If the tree is very tall, the fall of the coconut lasts long, and the  speed of the coconut keeps increasing. Since the air resistance is proportional to the speed, this means that at some point, the air resistance is no longer negligible, and it starts to have some effect on the fall of the coconut. In particular, at a certain point, the air resistance will become equal (in magnitude) to the force of gravity (but opposite in direction): this means that  from this point, the acceleration of the coconut will be zero, and therefore the coconut will continue its motion at constant velocity. This velocity is called terminal velocity, and it occurs when the force of gravity is equal to the air resistance:

mg = F_r

where F_r is the air resistance.

Learn more about forces and weight:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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Answer:

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Explanation:

Two points along a transverse wave (such as the one in the figure) are said to be in phase when:

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Basically, we say that two points are in phase when they are separated by a complete cycle (one complete oscillation) of the wave.

For this wave, we see that point B and C have same displacement, but they are not in phase since in B the oscillation is going down while in C is going up.

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