The answer is do not break, the key avoiding skids is to always smoothly apply your brakes and accelerator and to turn slowly and smoothly. Reducing of the speed before oncoming turns and once driving in possibly hazardous circumstances such as wet, icy or snow covered roadways or on roadways with loose gravel.
Answer:
"Why"
Explanation: A scientific law is a description of how the natural world behaves under certain circumstances.
These techniques are central to psychoanalytic therapy. They can be used alone or in combination with one another. Their purpose is to increase awareness and foster insight into the client's behavior and emotions
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Answer:
v = 66.4 m/s
Explanation:
As we know that plane is moving initially at speed of

now we have




now in Y direction we can use kinematics



since there is no acceleration in x direction so here in x direction velocity remains the same
so we will have



Answer:

Explanation:
The inital electrostatic force between the two spheres is given by:

where
is the initial force
k is the Coulomb's constant
q1 and q2 are the charges on the two spheres
r is the distance between the two spheres
The problem tells us that the two spheres are moved from a distance of r=20 cm to a distance of r'=10 cm. So we have

Therefore, the new electrostatic force will be

So the force has increased by a factor 4. By using
, we find
