Answer:
v = 49.69 km/hr
Explanation:
velcoity of truck with respect to car is given as = velocity of truck - velocity of car
velcoity of truck with respect to car is given as = (-54 sin(28)i +54cos(28)j - 91km/h
= -24.35i - 43.32j
magnitude of velocity is
v = 49.69 km/hr
the direction is
![tan^{-}[\frac{ 43.32}{24.35}]](https://tex.z-dn.net/?f=tan%5E%7B-%7D%5B%5Cfrac%7B%2043.32%7D%7B24.35%7D%5D)
= 60.65 degree towrd south of west
Power is the time rate of energy transfer. It doesn't matter whether it's
electrical, chemical, mechanical, muscular, wind, food, or hydro energy.
Answer:
No, it cannot. The car needs the friction of the surface to drive because the car pushes the surface backwards, and the surfaces makes a reaction force pushing the car forward, and that works because of the friction. In a frictionless surface the tires would rotate in the same place
You said 0.5 · m · v² = m · g · h
Divide each side by 'm' : 0.5 · v² = g · h
Multiply each side by 2 : v² = 2 · g · h
Square root each side : v = √(2 · g · h)
You said that g = 9.8 m/s² and h = 875 units
So v = √(9.8 m/s² · 875 units)
v = √(8,575 m·unit/s²)
v = 92.6 / s² · √(m · unit)
