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tiny-mole [99]
1 year ago
12

Calculate the ph of the solution that results following addition of 24 ml of 1.0 mnaoh to 60 ml of 1.0 mnh4cl.

Physics
1 answer:
Lostsunrise [7]1 year ago
4 0

The pH of the solution is 0.37.

<h3>What is the pH of the solution?</h3>

We can write the equation of the reaction as;

NH4Cl (aq) + NaOH (aq) ------- > NH3 (aq) + H2O (l) + NaCl (aq)

Number of moles of NaOH= 24/1000 * 1 = 0.024 moles

Number of moles of NH4Cl= 60/1000 * 1  = 0.060 moles

Given that the reaction is 1:1, the limiting reactant is NaOH

Number of moles of NH4Cl left over = 0.060 - 0.024 = 0.036 moles

Concentration of left  over NH4Cl = 0.036 moles/(24 + 60)/1000

= 0.43 moles

pH = -log(0.43)

pH = 0.37

Learn more about pH:brainly.com/question/15289741

#SPJ1

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The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7
My name is Ann [436]

Answer:

0.28 m

Explanation:

The following data were obtained from the question:

Force (F) = 5×10¯⁶ N

Charge 1 (q₁) = 6.7×10¯⁹ C

Charge 2 (q₂) = 6.7×10¯⁹ C

Electrical constant (K) = 9×10⁹ Nm²C¯²

Distance apart (r) =?

Thus, the distance between the two charges can be obtained as follow:

F = Kq₁q₂/r²

5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²

5×10¯⁶ = 4.0401×10¯⁷ / r²

Cross multiply

5×10¯⁶ × r² = 4.0401×10¯⁷

Divide both side by 5×10¯⁶

r² = 4.0401×10¯⁷ / 5×10¯⁶

Take the square root of both side

r = √(4.0401×10¯⁷ / 5×10¯⁶)

r = 0.28 m

Therefore, the distance between the two charges is 0.28 m

4 0
2 years ago
Supposing d(t) is known to have value D,
creativ13 [48]

Answer:

  • The procedure is: solve the quadratic equation for t.

Explanation:

This question assumes uniformly accelerated motion, for which the distance d a particle travels in time t is given by the general equation:

  • d(t)=d_0+v_0t+at^2/2

That is a quadratic equation, where the independent variable is the time t.

Thus, the procedure that will find the time t at which the distance value is known to be D is to solve the quadratic equation for t.

To solve it you start by changing the equation to the general form of the quadratic equations, rearranging the terms:

  • (a/2)t^2+v_0t+(d_0-D)=0

Some times that equation may be solved by factoring, and always it can be solved by using the quadratic formula:

  • t=\frac{-b+/-\sqrt{b^2-4ac} }{2a}

Where:

a=-a/2\\ \\ b=v_0\\ \\ c=d_0-D

That may have two solutions. Some times one of the solution makes no physical sense (for example time cannot be negative) but others the two solutions are valid.

5 0
3 years ago
3. Suppose that a block is pulled 16 meters across a floor. What amount of work is done if the force used to drag the block is 2
Nadusha1986 [10]

Explanation:

Work is the product of force and distance.

W = F×d

W = (22 N) × (16 m)

W = 352 J

7 0
3 years ago
While traveling along a highway a driver slows from 24 m/s to 15 m/s in 12 seconds. What is the automobile's acceleration? (Reme
djverab [1.8K]

Considering that while traveling on a road with a<u> final speed of 15 m/s</u>, and an<u> initial speed of 24 m/s</u>, with a given time <u>of 12 seconds.</u>

To calculate the acceleration, we apply the following formula:

α = Vf - Vo/t

We add our data into the formula and solve:

α = 15 m/s - 24 m/s/12 sec

α = -0.75 m/s²

Therefore, the acceleration of the car is -0.75 m/s².

<h2>Skandar</h2>
4 0
2 years ago
If the period of a given wave is 6 seconds what si the frequency of the wave
Veronika [31]
Frequency =1/period
Freq= 1/6= 0.17 Hertz
3 0
2 years ago
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