Question

Calculate the ph of the solution that results following addition of 24 ml of 1.0 mnaoh to 60 ml of 1.0 mnh4cl.

Answer 1

The pH of the solution is 0.37.

What is the pH of the solution?

We can write the equation of the reaction as;

$NH4Cl (aq) + NaOH (aq) ------- > NH3 (aq) + H2O (l) + NaCl (aq)$

Number of moles of $NaOH$= 24/1000 * 1 = 0.024 moles

Number of moles of $NH4Cl$= 60/1000 * 1  = 0.060 moles

Given that the reaction is 1:1, the limiting reactant is NaOH

Number of moles of NH4Cl left over = 0.060 - 0.024 = 0.036 moles

Concentration of left  over NH4Cl = 0.036 moles/(24 + 60)/1000

= 0.43 moles

pH = -log(0.43)

pH = 0.37

Learn more about pH:brainly.com/question/15289741

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