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1 year ago

Calculate the ph of the solution that results following addition of 24 ml of 1.0 mnaoh to 60 ml of 1.0 mnh4cl.

Physics

1 answer:

Lostsunrise [7]1 year ago

4 0

The pH of the solution is 0.37.

<h3>What is the pH of the solution?</h3>

We can write the equation of the reaction as;

$NH4Cl (aq) + NaOH (aq) ------- > NH3 (aq) + H2O (l) + NaCl (aq)$

Number of moles of $NaOH$ = 24/1000 * 1 = 0.024 moles

Number of moles of $NH4Cl$ = 60/1000 * 1 = 0.060 moles

Given that the reaction is 1:1, the limiting reactant is NaOH

Number of moles of NH4Cl left over = 0.060 - 0.024 = 0.036 moles

Concentration of left over NH4Cl = 0.036 moles/(24 + 60)/1000

= 0.43 moles

pH = -log(0.43)

pH = 0.37

Learn more about pH:brainly.com/question/15289741

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As per the question:

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Now, the distance the ball can penetrate to is given by:

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$\bar{h} = \frac{h}{2\pi} = \frac{6.626\times 10^{- 34}}{2\pi} = 1.0545\times 10^{- 34}\ Js$

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We can calculate the tunneling probability as:

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$P(t) = e^{-2.63\times 10^{32}}$

Taking log on both the sides:

$logP(t) = -2.63\times 10^{32} loge$

$P(t) = 10^{- 1.17\times 10^{32}}$

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