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horrorfan [7]
3 years ago
6

A bottle contains 3.100 ml of a liquid. the total mass of the bottle and the liquid together is 6.300 g. the mass of the empty b

ottle is 4.240 g. what is the density of the liquid? a 0.665 g/ml b 2.032 g/ml c 1.505 g/ml d 1.368 g/ml
Chemistry
2 answers:
Mariana [72]3 years ago
8 0

Answer : The density of the liquid is (a) 0.665 g/mL

Explanation : Given,

Volume of a liquid = 3.100 mL

Mass of empty bottle = 4.240 g

Total mass of bottle and the liquid = 6.300 g

First we have to calculate the mass of a liquid.

Mass of liquid + Mass of empty bottle = Total mass of bottle and liquid

Mass of liquid + 4.240 g = 6.300 g

Mass of liquid = 6.300 - 4.240 = 2.06 g

Now we have to calculate the density of a liquid.

Density=\frac{Mass}{Volume}

Density=\frac{2.06g}{3.100mL}=0.665g/mL

Therefore, the density of the liquid is 0.665 g/mL

Olenka [21]3 years ago
7 0
The answer is <span>a. 0.665 g/m</span>
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A 10-gram sample of zinc loses 560 J of heat and has a final temperature of 100
grandymaker [24]
<h3>Answer:</h3>

Initial temperature is 243.59°C

<h3>Explanation:</h3>

The quantity of heat is calculated by multiplying the mass of a substance by its specific heat capacity and change in temperature.

That is; Q = m×c×ΔT

In this case;

Quantity of heat = 560 J

Mass of the Sample of Zinc = 10 g

Final temperature = 100°C

We are required to determine the initial temperature;

This can be done by replacing the known variables in the formula of finding quantity of heat,

Specific heat capacity, c, of Zinc = 0.39 J/g.°C

Therefore,

560 J = 10 g × 0.39 J/g°C × ΔT

ΔT = 560 J ÷ (3.9 J/°C)

   = 143.59°C

But, since the sample of Zinc lost heat then the temperature change will have a negative value.

ΔT = -143.59°C

Then,

ΔT  = T(final) - T(initial)

Therefore,

T(initial) = T(final) - ΔT

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              = 243.59°C

Hence, the initial temperature of zinc sample is 243.59°C

5 0
3 years ago
34 atoms of carbon (C) react with 22 molecules of hydrogen gas (H2). How many molecules of methane (CH4) will be formed, and wha
kolbaska11 [484]

Answer:

11 molecules of CH4.

23 atoms of C is the leftover.

Explanation:

Hello!

In this case, for the formation of methane:

C+2H_2\rightarrow CH_4

We can see there is an excess of carbon based on their stoichiometry, because the needed amount of hydrogen gas molecules would be:

molecules _{H_2}=34atomC*\frac{2molec\ H_2}{1atomC} =68molec\ H_2

Thus, the formed molecules of methane are computed below:

molec\ CH_4=22molec\ H_2 *\frac{1molec\ CH_4}{2molmolec\ H_2} \\\\molec\ CH_4=11molec\ CH_4

In such a way, the leftover of carbon atoms are:

atoms \ C^{left over}=34-22molec\ H_2*\frac{1atoms C}{2molec\ H_2} \\\\atoms \ C^{left over}=23 atoms C

Best regards!

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2 years ago
If the map shows the average high temperature in July for two cities in Texas. like Del Rio=36°c
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Answer:

D

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Why melting point of Fe in blast furnace is lower than ellingham?
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Answer:

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