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hichkok12 [17]
3 years ago
10

Aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce

Chemistry
1 answer:
Nina [5.8K]3 years ago
8 0

Answer:

CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄

Explanation:

<em>The question is missing but I think it must be about writing and balancing the equation.</em>

Let's consider the unbalanced equation for the reaction that occurs when aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce  a precipitate of copper (II) fluoride (<em>I fixed a mistake here</em>) and aqueous potassium sulfate. This is a double displacement reaction.

CuSO₄(aq) + KF(aq) = CuF₂ + K₂SO₄

Since only K and F atoms are not balanced, we will get the balanced equation by multiplying KF by 2.

CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄

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Evgen [1.6K]

Answer:

Hmm, what can I help you with?

Explanation:

5 0
3 years ago
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explanation
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Sodium carbonate (Na2CO3) reacts with acetic acid (CH3COOH) to form sodium acetate (NaCH3COO), carbon dioxide (CO2), and water (
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Use the formula q=m×Cp×delta T

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I JUST FINISHED THIS QUESTION AND IT SAID THAT THE ANSWER WAS -3.72 kJ SO PUT THAT DOWN AS YOUR ANSWER....I'm not sure why the answer is negative, but this is the most work I can show. If any one knows, why this answer is negative, please advise. Thank you. I hope that this helps :)
7 0
3 years ago
Read 2 more answers
How many moles of Nitrogen in 40.0 g of N2O?<br> .14 g<br> 25.5 g<br> 14.5 g
Paul [167]

Answer:

To do this question. we first have to find the mass% of nitrogen in N2O and then, using that percentage, we can simply find the number of moles of N from the number of moles of N2O

<u></u>

<u>Mass % of Nitrogen:</u>

Mass% of nitrogen = (Molar mass of N2 / Molar mass of N2O)*100

Mass% nitrogen = (28 / 44)*100

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<u>Mass of Nitrogen:</u>

So, now we can say that in any given mass of N2O. 63% of the total mass is the mass of Nitrogen

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Replacing the variables

40 * 0.63 = Mass of Nitrogen

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