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hichkok12 [17]
3 years ago
10

Aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce

Chemistry
1 answer:
Nina [5.8K]3 years ago
8 0

Answer:

CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄

Explanation:

<em>The question is missing but I think it must be about writing and balancing the equation.</em>

Let's consider the unbalanced equation for the reaction that occurs when aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce  a precipitate of copper (II) fluoride (<em>I fixed a mistake here</em>) and aqueous potassium sulfate. This is a double displacement reaction.

CuSO₄(aq) + KF(aq) = CuF₂ + K₂SO₄

Since only K and F atoms are not balanced, we will get the balanced equation by multiplying KF by 2.

CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄

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  As we know that
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