Aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce

Chemistry

1 answer:

Nina [5.8K]3 years ago

8 0

Answer:

CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄

Explanation:

<em>The question is missing but I think it must be about writing and balancing the equation.</em>

Let's consider the unbalanced equation for the reaction that occurs when aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce a precipitate of copper (II) fluoride (<em>I fixed a mistake here</em>) and aqueous potassium sulfate. This is a double displacement reaction.

CuSO₄(aq) + KF(aq) = CuF₂ + K₂SO₄

Since only K and F atoms are not balanced, we will get the balanced equation by multiplying KF by 2.

CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄

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Desire I holp! Has't a most wondrous day!

Hope I helped! Have a great day!

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