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hichkok12 [17]
3 years ago
10

Aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce

Chemistry
1 answer:
Nina [5.8K]3 years ago
8 0

Answer:

CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄

Explanation:

<em>The question is missing but I think it must be about writing and balancing the equation.</em>

Let's consider the unbalanced equation for the reaction that occurs when aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce  a precipitate of copper (II) fluoride (<em>I fixed a mistake here</em>) and aqueous potassium sulfate. This is a double displacement reaction.

CuSO₄(aq) + KF(aq) = CuF₂ + K₂SO₄

Since only K and F atoms are not balanced, we will get the balanced equation by multiplying KF by 2.

CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄

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What happens when carbon dioxide is passed through lime water for a long time? write with equation​
Vlada [557]

Answer:

when CO2 gas is passed through lime water it turns milky due to the formation of calcium carbonate which formula is CaCO3.

Ca(OH)2+ CO2------ CaCO3

when excess of carbon dioxide is passed through calcium carbonate calcium hydrogen carbonate is formed and solution become colourless.

CaCO3+CO2------ Ca(HCO3)

5 0
3 years ago
What is the mass, in pounds, of 389 mL of a gas that has a density of 1.29 g/L?
devlian [24]

Answer: Mass of gas is 0.001 pounds.

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of gas = ?

Density of gas = 1.29g/L

Volume of gas = 389 ml = 0.389 L     (1L=1000ml)

Putting in the values we get:

1.29g/L=\frac{mass}{0.389L}

mass=0.5grams  

mass=0.5\times 0.002lb=0.001lb       (1g =0.002 lb)

Thus the mass of gas is 0.001 pounds.

7 0
3 years ago
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Tems11 [23]

Answer: A different group of scientists using different methods.

5 0
3 years ago
What are the charges on barium and fluorine in barium fluoride? 1 point Captionless Image Barium is +2 and fluorine is -2. Bariu
user100 [1]

Answer: Barium is +2, Fluorine is -1

Explanation:

The charge of barium is +2, and the charge of fluorine is -1. You can determine this from the periodic table groups.

The formula for barium fluoride is thus BaF2.

8 0
3 years ago
If the equilibrium concentrations of products are much greater than those of reactants in this system, what would be the magnitu
miss Akunina [59]

Answer:

K > 1.

Explanation:

∵ The equilibrium constant K = [products]/[reactants].

Since, [products] > [reactants].

<em>∴ The equilibrium constant K > 1.</em>

5 0
4 years ago
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