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lilavasa [31]
3 years ago
15

How many atoms of aluminum are in 4.9 mol of aluminum?​

Chemistry
1 answer:
Strike441 [17]3 years ago
6 0

Answer:

8.14 mols al

Explanation:

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Lisa needs to buy a helium tank to fill up all the balloons. If the helium must be compressed from an original volume of 27.0L a
algol13

Answer:

P_2=135.73psi

Explanation:

Hello,

In this case we use the Boyle's law which allows us to understand the volume-pressure behavior as an inversely proportional relationship:

V_1P_1=V_2P_2

Whereas we solve for P_2 as the required final pressure:

P_2=\frac{V_1P_1}{V_2} =\frac{27.0L*14.7psi}{3.00L}\\ \\P_2=135.73psi

Best regards.

7 0
3 years ago
Read 2 more answers
What is the h+ oh- and poh of solution with ph=3.67
Alexxx [7]
Hi I don’t know the answer is I don’t know but I hope someone helps u ph=3.67
7 0
2 years ago
What is the change in enthalpy when 11. 0 g of liquid mercury is heated by 15°c?
Vlad1618 [11]

Enthalpy change is the difference between energy used and energy gained. The change in enthalpy of the liquid mercury is 0.0231 kJ.

<h3>What is the enthalpy change?</h3>

Enthalpy change is the difference between the energy used to break chemical bonds and the energy gained by the products formed in a chemical reaction.

The enthalpy change is given by,

\rm \Delta H_{rxn} = \rm q_{rxn}

and,

\rm q = mc\Delta T

Given,

Mass of the liquid mercury (m) = 11.0 gm

The specific heat of mercury (c) = 0.14 J per g per degree Celsius

Temperature change = 15 degrees Celsius

Enthalpy change is calculated as:

\begin{aligned} \rm q &= \rm mc\Delta T\\\\&= 11 \times 0.14 \times 15\\\\&= 23.1 \;\rm J\end{aligned}

Therefore, 0.0231 kJ is the change in enthalpy.

Learn more about enthalpy change here:

brainly.com/question/10932978

#SPJ4

6 0
2 years ago
What is the net amount of energy released when one mole of h2o(?) is produced?
german
The net amount of energy produced can be obtained from a table of enthalpy change of formation, available online.

The enthalpy change of formation indicate how much energy the 1 mole of the product (H2O) has relative to the elemental reactants (H2 and O2).  In other words, the "lost" energy equals the heat/energy released. 

For water (H2O), this value is -285.8 if the final product is a liquid under standard conditions, and -241.82 if the product is in gas form which contains some energy that could be further released.  This means that if the final product (H2O) is in liquid form, energy released is 285.8 kJ/mol.

Since water is in liquid form under standard conditions, the first value (285.8 kJ/mol) is generally appropriate.
7 0
3 years ago
→
marin [14]

Answer:

[A]²

Explanation:

Since the formation is independent of D, D is 0 order.

Since a quadruples when it is doubled it can be written as

2A^X= 4

To find the unknown power we can assume A= 1 to make the math simple. So When a = 2 (Because you doubled it) raised to X power it will equal 4

so the unknown power is 2

Making the rate law

[a]²[b]⁰

or simply just

[A]²

8 0
3 years ago
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