1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Otrada [13]
2 years ago
10

What is the answers? Is my answer right?

Chemistry
1 answer:
V125BC [204]2 years ago
5 0

Answer:

I say the correct answers are primary and secondary and teriary.

Explanation:

I say you are right!!

You might be interested in
Which of the following are excited in ultraviolet photoelectron spectroscopy?
zavuch27 [327]

Answer:

D. Valance Electrons

Explanation:

6 0
2 years ago
or a particular isomer of C 8 H 18 , the combustion reaction produces 5104.1 kJ of heat per mole of C 8 H 18 ( g ) consumed, und
beks73 [17]

Answer:

The standard enthalpy of formation of this isomer of C_{8}H_{18} is -220.1 kJ/mol.

Explanation:

The given chemical reaction is as follows.

C_{8}H_{18}(g)+ \frac{25}{2}O_{2}(g) \rightarrow 8CO_{2}(g)+9H_{2}O(g)

\Delta H^{o}_{rxn}= -5104.1kJ/mol

The expression for the entropy change for the reaction is as follows.

\Delta H^{o}_{rxn}=[8\Delta H^{o}_{f}(CO_{2}) +9\Delta H^{o}_{f}(H_{2}O)]-[\Delta H^{o}_{f}(C_{8}H_{18})+ \frac{25}{2}\Delta H^{o}_{f}(O_{2})]

\Delta H^{o}_{f}(H_{2}O)= -241.8kJ/mol

\Delta H^{o}_{f}(CO_{2})= -393.5kJ/mol

\Delta H^{o}_{f}(O_{2})= 0kJ/mol

Substitute the all values in the entropy change expression.

-5104.1kJ/mol=[8(-393.5)+9(-241.8)kJ/mol]-[\Delta H^{o}_{f}(C_{8}H_{18})+ \frac{25}{2}(0)kJ/mol]

-5104.1kJ/mol=-5324.2kJ/mol -\Delta H^{o}_{f}(C_{8}H_{18})

\Delta H^{o}_{f}(C_{8}H_{18}) =-5324.2kJ/mol +5104.1kJ/mol

=-220.1kJ/mol

Therefore, The standard enthalpy of formation of this isomer of C_{8}H_{18} is -220.1 kJ/mol.

4 0
3 years ago
When air cools, water molecules lose energy and<br> or change into liquid form.
Delicious77 [7]
I think it’s called condensation or water vapor
5 0
2 years ago
If an atom of thorium-234 were to undergo beta emission twice, which atom would result?
AnnZ [28]

Answer:

The answer to your question is  U-234

Explanation:

Data

Thorium-234

beta emission twice

Definition

Beta emission is when a beta particle (electron) is emitted from an atomic nucleus.

First beta emission

                                            ²³⁴₉₀Th   ⇒    ²³⁴₉₁Pa + e⁻

Second beta emission

                                            ²³⁴₉₁ Pa   ⇒  ²³⁴₉₂U  + e⁻

The atom will be Uranium-324

6 0
3 years ago
Read 2 more answers
Methane (CH4), ammonia (NH3), and oxygen can react to form hydrogen cyanide (HCN) and water according to this equation:
disa [49]
Assuming the molar mass of oxygen is 18.01, you only need 16 grams (B) of oxygen because the molar mass of hydrogen is about 1 gram.
16+1+1=18
7 0
3 years ago
Other questions:
  • Suppose a friend says that we don't need to worry about the rising temperatures associated with global climate change. Her claim
    11·1 answer
  • Which equation represents a double replacement reaction
    7·2 answers
  • Hemoglobin, the oxygen-carrying protein in red blood cells, has four iron atoms per molecules ad contains 0.340 percent iron by
    14·1 answer
  • When water boils and evaporates, it reaches what temperature?
    12·1 answer
  • An inventor claims to have devised a closed cyclic engine which exchanges heat with cold and hot reservoirs at 25 and 350 ◦C, re
    10·1 answer
  • To make its second-highest energy level be its valence energy level (being filled with an octet of electrons) and possess a more
    14·2 answers
  • A naturally occurring element consists of three isotopes. The data for the isotopes are:
    14·1 answer
  • What are the favored geometrical arrangements for abn molecules for which the a atom has 2?
    14·1 answer
  • What determines how and atom reacts with different atoms
    5·1 answer
  • Hiiii :D !! I need help please :&gt;
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!