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My name is Ann [436]
2 years ago
13

I need help!!! please don't give me a random answer ​

Mathematics
1 answer:
kirill115 [55]2 years ago
5 0

Answer:

2r+5=p

Step-by-step explanation:

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Which of the following represents a solution to the equation d3 - 343?
Levart [38]
I don’t see any multiple choice but d3 -343 is factored as (d-7)(d^2+7d+49)
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3 years ago
Describe the faces, edges, verticals of each three dimensional figure. Then identify it.
EastWind [94]

When you have to describe a 3D shape you have to keep the following definitions in mind:

<em>1. The face of a 3D shape is a flat surface.</em>

The shape on the picture has 3 rectangular faces and 2 triangular faces, a total of 5 faces.

<em />

<em>2. The edge is where two faces meet.</em>

For the shape on the picture, there are 3 edges, where the rectangular faces meet each other, and then three edges where the rectangular faces meet each of the triangular faces, this shape has a total of 9 edges.

<em>3. The vertex is a corner, where the edges meet.</em>

There are three vertices on each end of the shape, so it has a total of 6 vertices.

A shape that has 5 faces, 9 edges, and 6 vertices is a triangular prism.

6 0
1 year ago
Factor completly x^2 -64
Hoochie [10]

∑ Hey, jillianwagler ⊃

Answer:

\left(x+8\right)\left(x-8\right)

Step-by-step explanation:

<u><em>⇒ Given info:</em></u>

<em>Factor completely </em>x^2 -64

<u><em>⇒ Solution:</em></u>

<em>Rewrite 64 as 8 ² because 8² is equal to 64. 8 ² = 8 × 8 = 64.</em>

<em />=x^2-8^2

Applying difference of two squares formula: x^2-y^2=\left(x+y\right)\left(x-y\right)

=x^2-8^2=\left(x+8\right)\left(x-8\right)\\

=\left(x+8\right)\left(x-8\right)

Answer~: \left(x+8\right)\left(x-8\right)

<u><em>xcookiex12</em></u>

<em>8/19/2022</em>

7 0
2 years ago
Which expression has a positive value?
Alexus [3.1K]

Answer:

C - 3 (negative 64 divided by 8) + 25 =1

Step-by-step explanation:

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3 years ago
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Find the volume of a cube that has a side length of:<br> 6x²y5
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Answer:

Are this form 1 question

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3 years ago
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