Answer:
a) there is s such that <u>r>s</u> and s is <u>positive</u>
b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r
Step-by-step explanation:
a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.
b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.
Answer:
a . domain 5,0,7,9,0
range -2,-2,-4,8,2
b. domain 2,4,8,9
range 1,2,4,11
Step-by-step explanation:
<h3>a is not a function</h3>
because function is a relationship in which each domain element occurs only once.
<h3>b is a function</h3>
To find the area of a rectangular prism multiply length by width by height.
If the problem has a variable take the two other dimensions and multiply them together. Then take that number and subtract it from the total to find the number that the variable equals.
4(0.5n-3)=n-0.25(12-8n)
2n-12=n-3+2n
2n-12=3n-3
2n-3n=-3+12
-n=9
n = -9
