Answer:
x=10
Step-by-step explanation:
There's a bit of lack of context but I think the question is just asking what variables to put in for Lucy and Howard. There seems to be no need to answer any math problem.
I suggest using the variables x and y or l for Lucy and h for Howard. Remember to use lowercase letters.
One solution x = 1, y = 4
Since you're looking for the chance that the defective player occurs twice, you need to find the chance your friend receives a defective player given that you also receive one. The chance you receive a defective player is 4%, or 0.04. If you friend also receives a defective player, then the chance of both occurring is 4% of 4%, or 0.04 * 0.04, which equals 0.0016. So the probability that you can a friend both receive a defective player is 0.16%.
B because it like equivalent
