<u>Answer-</u>
<em>The length of BC is </em><em>8 units.</em>
<u>Solution-</u>
Mid-Point Theorem-
The line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side.
As given,
AD = DB, so D is the mid point of AB
FA = FC, so F is the mid point of AC
Hence, DF is the line segment connecting the midpoints of two sides of a triangle.
Applying the theorem,
BC = 2DF = 2×4 = 8 units
Answer:
37.7
Step-by-step explanation:
ig
Answer:
-9A · √(5yA)
Step-by-step explanation:
The coefficient -3 stays the same.
45 factors into 5·9, which is helpful because 9 is a perfect square.
Thus, √45 = 3√5.
y cannot be factored. It stays under the radical.
A³ can be factored into A² (a perfect square) and A.
Thus,
-3√(45yA³) = -3 · 3√5 · √y · A · √A, or
= (-3)(3)(A) · √(5yA), or
= -9A · √(5yA)
7 is infinite 6 is 4/3 5 is zero 4 is negative 5/4
Step-by-step explanation:
is this a quadrilateral? or polygon or triangle?
what are the angles (I believe there should be at least an angle given) else PC can be any value that is positive
