If the triangle has 11 sides it not a triangle
cot x = cos x / sin x
cot x = .85 / .52 = 1.6346
19x³ + (14x + 4x³)=
You can assume that there is a 1 in front of the parentheses, so you can distribute the one to each term in the parentheses.
19x³ + 1(14x+4x³)=
19x³ + 14x + 4x³=
Then combine like terms to get 23x³ + 14x.
So 19x³ + 14x + 4x³= 23x³ + 14x
Answer:
This tells us that:
![A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%267%5C%5C5%26-8%5C%5C3%26-9%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
So we are saying we have scalars, c and d, such that:
.
So we want to find a way to express this as:
Ax=b where x is the scalar vector,
.
So we can write this as:
![\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%267%5C%5C5%26-8%5C%5C3%26-9%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dc%5C%5Cd%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-16%5C%5C3%5C%5C-15%5Cend%7Barray%7D%5Cright%5D)
Answer:
A. 4/8 + 2/4 =1 B.5/8 + 1/4 =0.875
C.6/8 + 3/4 =1.5 D.7/8 + 2/4 =1.375