Let
x-------> the width of the rectangular area
y------> the length of the rectangular area
we know that
y=x+15------> equation 1
perimeter of a rectangle=2*[x+y]
2x+2y <= 150-------> equation 2
substitute 1 in 2
2x+2*[x+15] <=150--------> 2x+2x+30 <=150----> 4x <=150-30
4x <= 120---------> x <= 30
the width of the rectangular area is at most 30 ft
y=x+15
for x=30
y=30+15------> y=45
the length of the rectangular area is at most 45 ft
see the attached figure
the solution is<span> the shaded area</span>
The believe the answer would be D.
Solution:
Given:

To determine if an ordered pair is a solution, we substitute the x and y-values into the inequality and check if it is true.
Thus,




Therefore, the correct answers are selected as shown below;
Answer:
a =12*sqrt(2)
Step-by-step explanation:
3. The Pythagorean theorem states
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
a^2 +21^2 = 27^2
a^2 +441 =729
Subtract 441 from each side
a^2 +441-441 = 729 -441
a^2 =288
Take the square root of each side
sqrt(a^2) = sqrt(288)
sqrt(xy) = sqrt(x)sqrt(y)
a = sqrt(144)sqrt(2)
a =12*sqrt(2)