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3 years ago

Question:

Physics

1 answer:

irinina [24]3 years ago

8 0

Answer:

$624\:\mathrm{m}$

Explanation:

We can use kinematics equation $\Delta x =v_it+\frac{1}{2}at^2$ .

What we're given:

$v_i$ of 100.0 m/s
$t$ of 12 s
$a$ of -8.0 $\mathrm{m/s^2}$

Solving for $\Delta x$ :

$\Delta x=100\cdot 12+\frac{1}{2}\cdot -8\cdot 12^2=\boxed{624\:\mathrm{m}}$

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Which data set has the largest standard deviation

AfilCa [17]

Answer:

The data set marked as B has the largest standard deviation

Explanation:

Standard Deviation

It's a number used to show how a set of measurements is spread out from the average value. A low standard deviation means that most of the values are close to the average. A high standard deviation means that the numbers are more spread out.

The formula for the standard deviation is

$\displaystyle \sigma=\sqrt{\frac{\sum (x_i-\mu)^2}{n}}$

Where $x_i$ is the value of each measurement, n is the number of elements in the set, and $\mu$ is the average or media of the values, defined as

$\displaystyle \mu=\frac{\sum x_i}{n}$

Let's analyze each set of data:

A.3,4,3,4,3,4,3

The average is

$\displaystyle \mu=\frac{3+4+3+4+3+4+3}{7}=3.43$

Computing the stardard deviation:

$\sigma=\sqrt{\frac{(3-3.43)^2+(4-3.43)^2+(3-3.43)^2+(4-3.43)^2+(3-3.43)^2+(4-3.43)^2+(3-3.43)^2}{7}}$

$\sigma=0.5$

B.1,6,3,15,4,12,8

The average is

$\displaystyle \mu=\frac{1+6+3+15+4+12+8}{7}=7$

Computing the stardard deviation:

$\sigma=\sqrt{\frac{(1-7)^2+(6-7)^2+(3-7)^2+(15-7)^2+(4-7)^2+(12-7)^2+(8-7)^2}{7}}$

$\sigma=4.7$

C. 20, 21,23,19,19,20,20

The average is

$\displaystyle \mu=\frac{20+21+23+19+19+20+20}{7}=20.29$

Computing the stardard deviation:

$\sigma=\sqrt{\frac{(20-20.29)^2+(21-20.29)^2+(23-20.29)^2+(19-20.29)^2+(19-20.29)^2+(20-20.29)^2+(20-20.29)^2}{7}}$

$\sigma=1.3$

D.12,14,13,14,12,13,12

The average is

$\displaystyle \mu=\frac{12+14+13+14+12+13+12}{7}=12.86$

Computing the stardard deviation:

$\sigma=\sqrt{\frac{(12-12.86)^2+(14-12.86)^2+(13-12.86)^2+(14-12.86)^2+(12-12.86)^2+(13-12.86)^2+(12-12.86)^2}{7}}$

$\sigma=0.8$

We can see the data set marked as B has the largest standard deviation

5 0

4 years ago

Bob read data from the projectile motion lab graph shown and determined that the drop time was inversely proportional to the hor

Alecsey [184]

When he determined that the drop time was inversely proportional to the horizontal velocity, the answer for it would be Bob's conclusion was right because the data points were connected. The connection of the x and y axis varied because it is inversely proportional.

3 0

4 years ago

Read 2 more answers

A force vector has a magnitude of 599 newtons and points at an angle of 40.8° below the positive x axis. What is the x scalar co

ASHA 777 [7]

Answer:

$F_{x}=453.44N$

Explanation:

Given data

Force F=599 N

Angle α=40.8°

To find

x scalar component

Solution

The Scalar x component can be found by

$F_{x}=FCos\alpha \\F_{x}=599Cos(40.8)\\F_{x}=453.44N$

The Scalar y component can be found by

$F_{y}=-FSin\alpha \\F_{y}=-599Sin(40.8)\\F_{y}=-391.4N$

3 0

3 years ago

In a charming 19th-century hotel, an old-style elevator is connected to a counterweight by a cable that passes over a rotating d

melisa1 [442]

Answer:

2.38732 rpm

1.22625 rad/s²

163.292°

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

a = Acceleration = $\frac{1}{8}g$

d = Diameter of wheel = 2 m

r = Radius of wheel = $\frac{d}{2}=\frac{2}{2}=1\ m$

v = Speed of elevator = 25 cm/s

Angular speed is given by

$\omega=\frac{v}{r}\\\Rightarrow \omega=\frac{0.25}{1}\\\Rightarrow \omega=0.25\ rad/s=0.25\times \frac{60}{2\pi}\\\Rightarrow \omega=2.38732\ rpm$

The angular speed of the wheel is 2.38732 rpm

Angular acceleration is given by

$\alpha=\frac{a}{r}\\\Rightarrow \alpha=\frac{\frac{1}{8}g}{r}\\\Rightarrow \alpha=\frac{\frac{1}{8}\times 9.81}{1}\\\Rightarrow \alpha=1.22625\ rad/s^2$

The angular acceleration of the wheel is 1.22625 rad/s²

Angular displacement is given by

$\theta=\frac{s}{r}\\\Rightarrow \theta=\frac{2.85}{1}\\\Rightarrow \theta=2.85\ rad=2.85\times \frac{360}{2\pi}\\ =163.292\ ^{\circ}$

The angle the disk turned when it has raised the elevator is 163.292°

4 0

3 years ago

I need help thank you

Brums [2.3K]

Answer:

Explanation:

3 0

3 years ago