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snow_lady [41]
3 years ago
5

How do the magnetic and electrical components of electromagnetic waves travel in relation to each other? at right angles toward

each other in a circular motion parallel to each other
Physics
1 answer:
Nadusha1986 [10]3 years ago
3 0

A at right angles
•

The movement produces oscillating electric and magnetic fields, which travel at right angles to each other in a bundle of light energy called a photon. ... Magnetic and electric fields of an electromagnetic wave are perpendicular to each other and to the direction of the wave
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The rate at which work is done is known as which of the following?
sveta [45]

Answer:

A , power

Explanation:

Hope this is useful. Have a lovely rest of your day! God bless you.

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a the average distance from the Sun to Pluto is approximately 6.10 x 1 0 ^9. how long does it take light from the sun to reach P
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3 years ago
Letting D D represent the maximum displacement, the extremes of the block's motion are at position A, where x = − D x=−D, and at
Ksju [112]

Answer:

The answer is at x = 0, which represents position B

Explanation:

The full question is:

"A block is attached to a horizontal spring and set in a

simple harmonic motion, as shown from above in the figure. When the spring is relaxed, the block is a position B, where the displacement x from the equilibrium position is 0. Letting D represent the maximum displacement, the extremes of the block's motion are at position A, where x= -D, and at position C, where x= D.

At what point in the motion is the speed of the block at its maximum?"

And you can see the figure on the attached file.

Simple Harmonic motion equations

We can start from the equation that describes the position that is

x(t)=D \sin\left(\omega t)

Here D stands for the amplitude which is the maximum displacement, and \omega is the angular velocity, thus we can find the derivative to find the velocity equation, so we get

v(t)=D \omega \cos (\omega t)

And we can find the derivative again to find the acceleration.

a(t) = -D\omega^2 \sin (\omega t)

Maximum speed

We reach the maximum speed when the acceleration equation is equal to 0,

a(t) =0\\-D\omega^2 \sin (\omega t)=0

Thus it happens when

\sin (\omega t)=0

So if we replace that on the position equation we get

x(t)=D \sin(\omega t) \\x(t)=D(0)\\x(t)=0

Thus the position where the speed of the block is at at its maximum is when it is going back to the origin, that is x = 0, so point b.

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3 years ago
Jorge has made a hypothesis that the more you feed him out the shinier it’s fur will be because the mouse will be healthier
guapka [62]

I think the correct answer is B

8 0
3 years ago
Read 2 more answers
4. What instrument is used to measure mass?​
givi [52]

Answer:

A Beam balance (or Beam scale) is a device to measure weight or mass.

Explanation:

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3 years ago
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