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Ad libitum [116K]
3 years ago
6

I need to know the temperature changes

Physics
1 answer:
Arada [10]3 years ago
5 0
What are you asking? And more info needs to be provided.
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Find the angular momentum of a hollow spinning sphere when its angular speed is 20rad/s. The rotational inertia of the sphere is
zysi [14]

Answer:

L= 0.4 kgm²/s

Explanation:

The angular momentum of a hallow spinning sphere is

L = Iω

L = (0.02kgm²) × (20rad/s)

L= 0.4kgm²/s

5 0
2 years ago
What is the only "power" unit of measurement in light energy?
n200080 [17]
I believe it wattage or watts
8 0
3 years ago
(PLEASE HELP THANK YOU) A car is going 8 meters per second on an access road into a highway and then accelerates at 1.8 meters p
jonny [76]

Answer:

20.96 m/s

Explanation:

Apply the kinematic equation:

Vf=Vi+at

Vi=8m/s

a=1.8m/s^2

t=7.2s

Putting this all in should give you your answer of 12.96m/s

6 0
3 years ago
The reflective surface of a CD consists of spirals of equally spaced grooves. If you shine a laser pointer on a CD, each groove
Ipatiy [6.2K]

Answer:

d = 1.55 * 10⁻⁶ m

Explanation:

To calculate the distance between the adjacent grooves of the CD, use the formula, d = \frac{m \lambda}{sin(A_{m}) }..........(1)

The fringe number, m = 1 since it is a first order maximum

The wavelength of the green laser pointer, \lambda = 532 nm = 532 * 10⁻⁹ m

Distance between the central maximum and the first order maximum = 1.1 m

Distance between the screen and the CD = 3 m

A_{m} = Angle between the incident light and the diffracted light

From the setup shown in the attachment, it is a right angled triangle in which

sin(A_{m}) = \frac{opposite}{Hypotenuse} \\sin(A_{m}) =\frac{1.1}{\sqrt{1.1^{2}+3^{2}}}

sin(A_{m} ) = 0.344\\A_{m} = sin^{-1} 0.344\\A_{m} = 20.14^{0}

Putting all appropriate values into equation (1)

d = \frac{1* 532*10^{-9} }{0.344 }\\d = 0.00000155 m\\d = 1.55 * 10^{-6} m

3 0
3 years ago
Two sets of Christmas lights are available. For set A, when one bulb is removed, the remaining bulbs remain illuminated. For set
Paul [167]

Explanation:

Bulbs are nothing but resistors that glow when current passes through them.

In Set A, the bulbs (resistors) are connected  parallely to each other, this means that even if one of the bulbs fuses or removed, the circuit will still be completed and others continue to glow.

And in parallel connection if the resistance of the two resistors are same  powered delivered to each is same.

In Set B, bulbs are in series connection, this means that when one of the bulb is removed or fuses, the circuit will break and other bulbs can not operate.In this situation as well  if the resistance of two resistors is same then the power delivered is same.

7 0
3 years ago
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