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Anon25 [30]
3 years ago
7

Consider a memory-management system based on paging. The total size of the physical memory is 2 GB, laid out over pages of size

8 KB. The logical address space of each process has been limited to 256 MB. a. Determine the total number of bits in the physical address. b. Determine the number of bits specifying page replacement and the number of bits for page frame number. c. Determine the number of page frames. d. Determine the logical address layout.
Computers and Technology
1 answer:
Sliva [168]3 years ago
4 0

Answer:

A. 31 bits

B. 13 bits, 18 bits

C. 256k

Explanation:

A.

We have total size of physical memory as 2gb

This means that 2¹ x 2³⁰

Using the law of indices,

= 2³¹

So physical address is equal to 31 bits

B.

We get page size = 8kb = 2³

1 kb = 2¹⁰

2³ * 2¹⁰ = 2¹³

So page replacement = 13 bits

Page frame number

= physical address - replacement bits

= 31 - 13

= 18 bits

C.

The number of frames is given as

2¹⁸ = 2⁸ x 2¹⁰ = 256K

So number of frames = 256K

D

Logical add space is 256K

Page size= physical pages = 8kb

Logical address layout= 28biys

Page number = 15 bits

Displacement = 12 bits

256k/8k = 32 pages in address space process

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Answer:

The solution code is written in Python 3

  1. total = 0
  2. count = 0
  3. neg = 0
  4. pos = 0
  5. num = int(input("Enter an integer: "))
  6. while(num != 0):
  7.    total += num  
  8.    count += 1
  9.    if(num < 0):
  10.        neg += 1
  11.    else:
  12.        pos += 1
  13.    num = int(input("Enter an integer: "))
  14. print("The number of positives: " + str(pos))
  15. print("The number of negatives: " + str(neg))
  16. print("The total is " + str(total))
  17. print("The average is " + str(total/count))

Explanation:

Firstly, we create four variables, <em>total</em> , <em>count,</em> <em>neg</em> and <em>pos </em>(Line 1- 4). This is to prepare the variable to hold the value of summation of input integer (<em>total</em>), total number of input number (<em>count</em>), total negatives (<em>neg</em>) and total positives (<em>pos</em>).

Next, we prompt user for the first integer (Line 6).

Create a sentinel while loop and set the condition so long as the current input number, <em>num</em> is not equal to zero. the program will just keep adding the current <em>num</em> to total (Line 9)  and increment the count by one (Line 10).

if <em>num</em> smaller than zero, increment the <em>neg</em> by one (Line 13) else increment the <em>pos </em>by one (Line 15). This is to track the total number of positives and negatives.

Finally, we can display all the required output (Line 20 - 23) using the Python built-in function <em>print()</em>  when user enter 0 to terminate the while loop. The output shall be as follows:

The number of positives: 3

The number of negatives: 1

The total is 5

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Answer:

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Explanation:

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def getCharacterForward(char, key): """ Given a character char, and an integer key, the function shifts char forward `key` steps
zhenek [66]

Answer:

  1. def getCharacterForward(char, key):  
  2.    charList = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
  3.    if(len(char) > 1):
  4.        return None  
  5.    elif(not isinstance(key, int)):
  6.        return -1
  7.    else:
  8.        index = charList.find(char)
  9.        if(index + key <= 25):
  10.            return charList[index + key]
  11.        else:
  12.            return charList[(index + key)% 26]
  13. print(getCharacterForward("C", 4))
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Explanation:

Firstly, define a charList that includes all uppercase alphabets (Line 2). We presume this program will only handle uppercase characters.

Follow the question requirement and define necessary input validation such as checking if the char is a single character (Line 4). We can do the validation by checking if the length of the char is more than 1, if so, this is not a single character and should return None (Line 5). Next, validate the key by using isinstance function to see if this is an integer. If this is not an integer return -1 (Line 6 - 7).

Otherwise, the program will proceed to find the index of char in the charList using find method (Line 9). Next, we can add the key to index and use the result value to get forwarded character from the charList and return it as output (Line 11).

However, we need to deal a situation that the char is found at close end of the charList and the forward key steps will be out of range of alphabet list. For example the char is X and the key is 4, the four steps forward will result in out of range error. To handle this situation, we can move the last two forward steps from the starting point of the charList. So X move forward 4 will become B. We can implement this logic by having index + key modulus by 26 (Line 13).  

We can test the function will passing two sample set of arguments (Line 15 - 16) and we shall get the output as follows:

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