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Rasek [7]
2 years ago
7

Output each floating-point value with two digits after the decimal point, which can be achieved by executing cout << fixed

<< setprecision(2); once before all other cout statements. (1) Prompt the user to enter five numbers, being five people's weights. Store the numbers in a vector of doubles. Output the vector's numbers on one line, each number followed by one space. (2 pts)
Computers and Technology
1 answer:
Fofino [41]2 years ago
5 0

Answer:

In C++:

#include <iomanip>

#include <iostream>

#include <vector>

using namespace std;

int main(){

vector<double> myvector;

double userinput;

cout<<"Enter 5 numbers: ";

for (int i = 1; i <= 5; i++){

 cin>>userinput;

    myvector.push_back(userinput);

}

for (int i = 0; i < 5; i++){

    cout << fixed << setprecision(2)<< myvector.at(i) <<' ';

}

return 0;

}

Explanation:

This declares the vector as double

 vector<double> myvector;

This declares a variable for input as double

double userinput;

This prompts the user for input of 5 numbers

cout<<"Enter 5 numbers: ";

This iterates from 1 to 5

for (int i = 1; i <= 5; i++){

This gets each integer input

 cin>>userinput;

This pushes each input into the vector

    myvector.push_back(userinput); }

This iterates through the vector

for (int i = 0; i < 5; i++){

This prints each vector element separated by space using fixed setprecision

cout << fixed << setprecision(2)<< myvector.at(i) <<' ';

}

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4 0
2 years ago
Input 3 positive integers from the terminal, determine if tlrey are valid sides of a triangle. If the sides do form a valid tria
butalik [34]

Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

       if side1 == side2 == side3:

           print("Equilateral Triangle")

       elif side1 == side2 or side1 == side3 or side2 == side3:

           print("Isosceles Triangle")

       else:

           print("Scalene Triangle")

   else:

       print("Invalid Triangle")

else:

   print("Invalid Triangle")

Explanation:

The next three lines get the input of the sides of the triangle

<em>side1 = float(input("Side 1: ")) </em>

<em>side2 = float(input("Side 2: ")) </em>

<em>side3 = float(input("Side 3: ")) </em>

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

<em>        if side1 == side2 == side3: </em>

<em>            print("Equilateral Triangle") </em>

Check if the triangle is isosceles

<em>        elif side1 == side2 or side1 == side3 or side2 == side3: </em>

<em>            print("Isosceles Triangle") </em>

Otherwise, it is scalene

<em>        else: </em>

<em>            print("Scalene Triangle") </em>

Print invalid, if the sides do not make a valid triangle

<em>    else: </em>

<em>        print("Invalid Triangle") </em>

Print invalid, if the any of the sides are negative

<em>else: </em>

<em>    print("Invalid Triangle")</em>

4 0
3 years ago
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