Answer:
This is simple, if it has a high flammability, and you light it on fire, then that would be a chemical change.
Explanation:
May I have brainliest please? :)
Mass of the compound = 205 g
Molar Mass of compound = ((24) + (2 * 32) + (3 * 16))
= 136 g / mol
∴ # mols in 205g =
= 1.507 mol
Here we have to calculate the number of moles of valuable propane can be prepared from 1.8 moles of carbon.
From 1.8 moles of carbon 0.3 moles of propane can be prepared by the reaction.
From 6 moles of carbon (C) 1 moles of valuable propane (C₃H₈) can be prepared.
Thus from 1.8 moles of C we can obtain ×1.8 = 0.3 moles of the propane can be prepared.
Thus the amount of propane produced in this reaction is determined.
Have about 5 beakers all with different temperatures of water. Put in a teaspoon of salt at a time and when it stops dissolving stop adding and record how much salt it took. It should be more salt as the temperature rises. The independent variable is the waters temperature. The dependent variable is how much salt is used. Make sure that there is the same amount of water in each beaker. Or else it won’t work.