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rodikova [14]
3 years ago
8

Picture attached, $3

Chemistry
1 answer:
Luba_88 [7]3 years ago
6 0

Answer:

its -000.5

Explanation:

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What explanation accounts for the observation that the mass of the products in reaction #1 (open system) were not equal?
Anna007 [38]

Answer:

The law of conservation of mass states that matter can not be created or destroyed in a chemical reaction.

Explanation:

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2 years ago
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Explanation:

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2 years ago
How many liters of 1.5 M potassium permanganate could be made if 152 g of the solute are available?
Misha Larkins [42]

Answer:

0.64 L

Explanation:

Recall that

n= CV where n=m/M

Hence:

m/M= CV

m= given mass of solute =152g

M= molar mass of solute

C= concentration of solute in molL-1 = 1.5M

V= volume of solute =????

Molar mass of potassium permanganate= 158.034 g/mol

Thus;

152 g/158.034 gmol-1= 1.5M × V

V= 0.96/1.5

V= 0.64 L

6 0
3 years ago
Read 2 more answers
SnO2 + 2 H2 ——> Sn + 2 H2O
SpyIntel [72]

Answer:

0.15g

Explanation:

Given parameters:

Number of molecules of water = 1.2 x 10²¹ molecules

Unknown:

Mass of SnO₂  = ?

Solution:

To solve this problem, we have to work from the known to the unknown specie;

             SnO₂   +    2H₂    →   Sn  +   2H₂O

Ensure that the equation given is balanced;

       

Now,

          the known species is water;

                  6.02 x 10²³ molecules of water  = 1 mole

                   1.2 x 10²¹ molecules of water  = \frac{1.2 x 10^{21} }{6.02 x 10^{23} }    = 0.2 x 10⁻²moles

Number of moles of water  = 0.002moles

           From the balanced chemical equation:

         

             2 mole of water is produced from 1 mole of    SnO₂  

           0.002 moles of water will be produced from \frac{0.002}{2}  = 0.001moles

To find the mass;

           Mass  = number of moles x molar mass

Molar mass of  SnO₂ = 118.7 + 2(16) = 150.7g/mol

        Mass  =  0.001 x 150.7 = 0.15g

3 0
3 years ago
What is an oxidation state?
Oxana [17]

Answer:

Oxidation state shows the total number of electrons which have been removed from an element (a positive oxidation state) or added to an element (a negative oxidation state) to get to its present state

4 0
3 years ago
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