I think it’s d
If it’s wrong then I’m sorry
Explanation:
The solution of the lactic acd and sodium lactate is referred to as a buffer solution.
A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa. In this case, the weak acid is the lactic acid and the conjugate base is the sodium lactate.
Buffer solutions are generally known to resist change in pH values.
When a strong base (in this case, NaOH) is added to the buffer, the lactic acid will give up its H+ in order to transform the base (OH-) into water (H2O) and the conjugate base, so we have:
HA + OH- → A- + H2O.
Since the added OH- is consumed by this reaction, the pH will change only slightly.
The NaOH reacts with the weak acid present in the buffer sollution.
Answer:
0.68g/ml
Explanation:
The density of an object is its mass per unit volume. It is calculated using the formula
Density = mass / volume
Mass of stopper weighed = 4.8g
The volume of stopper can be got by subtracting the (volume of water) from the (volume of water+stopper) i.e.
= 39.2ml - 32.1ml
= 7.1ml
Volume of stopper = 7.1ml
Density of stopper= 4.8/7.1
Density= 0.676056
Therefore, the density of the stopper is 0.68g/ml
