Which pair of elements is most likely to form an ionic compound with each other?

Find the molecular mass of<br>MgSO4 7H₂O.

mario62 [17]

Answer:

MgO +H2SO4

Explanation:

use photomath

7 0

3 years ago

PtichkaEL [24]

Answer:

c) 35 fl oz

Explanation:

Hello,

In this case, to compute the recommended amount of calcium that the teenager must drink, one performs the following relationship:

$8.0-fl \ oz -->298mg\\x-->1,300mg$

Solving for $x$ , one gets:

$x=\frac{8.0-fl \ oz *1,300mg}{298mg} \\x=35-fl \ oz$

Best regards.

5 0

4 years ago

Teo3 lewis structure

svetoff [14.1K]

Answer:

here. hope it helps!

Explanation:

5 0

1 year ago

Decreasing the saturation of the fatty acid chains on a particular type of phospholipid would result in the formation of _____.

LUCKY_DIMON [66]

Answer:

The correct answer is "more fluid bilayers".

Explanation:

A fatty acid is a biomolecule of lipidic nature formed by a long hydrocarbon chain of different lengths at the end of which there is a carboxyl group.

The wall of the gallbladder consists of three main layers of tissue: The mucosa covers the wall of the gallbladder. The muscular layer of smooth muscle. The serosa, which is the outer layer.

By decreasing the saturation of the fatty acid chains in phospholipids, the bile layers would reduce their thickness and become more fluid.

Have a nice day!

3 0

4 years ago

Estimate ΔH for the reaction: C2H6(g) + Cl2(g)--> C2H5Cl(g) + HCl(g) given the following average bond energies (in kJ/mol): C

Leno4ka [110]

Explanation:

The reaction equation will be as follows.

$C_{2}H_{6}(g) + Cl_{2}(g) \rightarrow C_{2}H_{5}Cl(g) + HCl(g)$

Using bond energies, expression for calculating the value of $\Delta H$ is as follows.

$\Delta H = \sum B.E_{reactants} - \sum B.E_{products}$

On reactant side, from $C_{2}H_{6}$ number of bonds are as follows.

C-C bonds = 1

C-H bonds = 6

From $Cl_{2}$ ; Cl-Cl bonds = 1

On product side, from $C_{2}H_{5}Cl$ number of bonds are as follows.

C-C bonds = 1

C-H bonds = 5

C-Cl bonds = 1

From HCl; H-Cl bonds = 1

Hence, using the bond energies we will calculate the enthalpy of reaction as follows.

$\Delta H = \sum B.E_{reactants} - \sum B.E_{products}$

= $[(1 \times 348 kJ/mol) + (6 \times 414 kJ/mol) + (1 \times 242 kJ/mol)] - [(1 \times 348 kJ/mol) + (5 \times 414 kJ/mol) + (1 \times 327 kJ/mol) + (1 \times 431 kJ/mol)]$ = -102 kJ/mol

Thus, we can conclude that change in enthalpy for the given reaction is -102 kJ/mol.

5 0

3 years ago