The answer to the problem is:
<span>8j^3 + 5j^2 - 3 - 5j^3 - 7j^2 + 12j - 7
</span>
<span>3j^3 - 2j^2 + 12j - 10
</span>
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Answer:
1) x-2y 2) 2(13a-5)
Step-by-step explanation:
1) -1/2(-2x+4y)=2/2x-4/2y=x-2y
2) 26a-10=2(13a-5)
Answer:
cos 240 deg = -1/2 and sin 240 = - root(3)/2
Step-by-step explanation:
if cos 60° = 1/2 and sin 60º = root 3/2 find cos 240° and sin 240".
we know that cos 240 = cos (60 + 180) = - cos 60 = - 1/2
cosine is negative when the angle is in the 3rd quadrant
sin 240 = sin (60 + 180) = - root(3) /2
sine is also negative in the 3rd quadrant.
