Given:
Point D is incenter of ΔBCA.
m∠FDG = 136°
To find:
The measure of ∠FHG
Solution:
<em>Angle subtended by the arc at the center is twice that subtended on the remain part of the circle.</em>
Divided by 2 on both sides.
Substitute m∠FDG = 136°
The measure of ∠FHG is 68°.
The answer would be D) 40x^2+65x+25
Hope this helps :)
please make this answer the brainiest it would really help me. thanks :)
Answer:
y=-2x-4
Step-by-step explanation:
y-y1=m(x-x1)
y-0=-2(x-(-2))
y-0=-2(x+2)
y=-2x-4+0
y=-2x-4
In this exercise we have assumption:
x-4>0
x>4
from this we know domain : x∈(4,+infinity)
range y∈R
Find a common denominator that 8 and 3 can go into.. which is 24
5/8 = 1/3
15/24 - 8/24
7/24
Hope this helped
