1/1×3+1/2×4+1/3×5 +...+1/18×20= Please, help me. ❣️

Omari and his two cousins received the same amount of money to go to the movies. Each boy spent $15. Afterward, the boys had $30

Jlenok [28]

Answer:

Each boy recieved $25.25 each

Step-by-step explanation:

First, you add up all the money the 3 boys spent.

15+15+15=45

Then you add the sum of the equation to the amount all the boys had afterward.

45+30.75=75.75

Finally, you divide that product to 3 boys.

75.75/3=25.25

Therfore the answer is $25.25 each.

6 0

3 years ago

Consider the quadratic equation x2 − 6x = 16.

e-lub [12.9K]

Answer:

C) (x − 3)2 = 25
C) Factor out 4 from 4x2 + 40x.

Step-by-step explanation:

1. Adding the square of half the x-coefficient to both sides of the equation will "complete the square." That square is 9, so the result on the right is 16+9 = 25. Only selection C matches.

___

2. To complete the square, you want to be able to put the quadratic into the form a(x -h)^2 = -k. For the purpose, it is most convenient to first factor "a" from the given quadratic. Then you can determine "-h" to be half the x-coefficient inside the parentheses.

Here, that looks like ...

4(x² +10x) = 80 . . . . . . . . . . step 1: factor out 4

4(x² +10x +25) = 180 . . . . . add 25 inside parentheses and the same number (4·25) on the right side of the equation

4(x +5)² = 180 . . . . . . . . . . . written as a square

8 0

3 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let X = number of vehicles that pass the inspection.

The probability of the random variable X is P (X) = 0.70.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let X = all 3 vehicle passes and Y = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

3 years ago

Please help! no rush though :)

gtnhenbr [62]

Answer:

160000 kg and 8000

Step-by-step explanation:

move decimal to the right five times

move decimals to right 3 times

6 0

3 years ago

How do you write numbers without scientific notation

grigory [225]

How do write whole numbers without scientific notation? can you elaborate on your question.

6 0

3 years ago

1/1×3+1/2×4+1/3×5 +...+1/18×20=Please, help me. ❣️​

1/1×3+1/2×4+1/3×5 +...+1/18×20=Please, help me. ❣️