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Harrizon [31]
3 years ago
9

A sweater is marked down $25 to $19 what is the percent of change

Mathematics
1 answer:
Marrrta [24]3 years ago
7 0
19/25 = x/100
Cross multiply:
1,900
Divide 1,900 by 25
Equals 76
Subtract 76 from 100
Answer: 24% change

I hope this helps!
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What is this value? giving thanks and marking brainliest :)
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x = 23 degress

Step-by-step explanation:

(x + 2) + 65 = 90

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<u>x = 23 degress</u>

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Each side of a square office is 8 yards long. It will cost $65.00 per square yard to replace the carpet in the office. What woul
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Which of the following statements is true according to the measurements in the diagram?
e-lub [12.9K]

Let's look at the corresponding ratios:

\frac{AB}{ED}=\frac{24}{30}=\frac{4}{5}\\\frac{BC}{DC}=\frac{16}{20}=\frac{4}{5}\\\frac{AC}{EC}=\frac{21}{28}=\frac{3}{4}\\

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Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
3 years ago
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