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jenyasd209 [6]
3 years ago
12

Suppose the random variables X, Y, and Z have the following joint probability distribution. x y z f ( x , y , z ) 1 1 1 0.05 1 1

2 0.10 1 2 1 0.15 1 2 2 0.20 2 1 1 0.20 2 1 2 0.15 2 2 1 0.10 2 2 2 0.05 Determine the conditional probability distribution of X given that Y
Mathematics
1 answer:
Airida [17]3 years ago
3 0

Answer:

Determine the conditional probability distribution of X given that Y = 1 and Z = 2. Round your answers to two decimal places (e.g. 98.76).

answer:

Given that Y = 1 :  2/5

Given that Z = 2 : 3/5

Step-by-step explanation:

The conditional probability distribution of X     F x | yz^( x )

Given that Y = 1

F x | yz . ( x | yz )  = 2/5

Given that z = 2

= 3/5

attached below is the detailed solution

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tankabanditka [31]

Answer:

1/5 + 2/5 i sqrt(6) = .2 + .98i

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Step-by-step explanation:

5z^2−9z=−7z−5

We need to get all the terms on one side (set the right side equal to zero)

Add 7z to each side

5z^2−9z+7z=−7z+7z−5

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where a = 5   b = -2  and c = 5

-b± sqrt(b^2-4ac)

-------------------------

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-(-2)± sqrt((-2)^2-4(5)5)

-------------------------

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2± sqrt(4-100)

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2± sqrt(-96)

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2± sqrt(16)sqrt(-1) sqrt(6)

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2± 4i sqrt(6)

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1/5 ± 2/5 i sqrt(6)

Splitting the ±

1/5 + 2/5 i sqrt(6) = .2 + .98i

1/5 - 2/5 i sqrt(6) = .2 - .98i


3 0
3 years ago
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