Suppose the random variables X, Y, and Z have the following joint probability distribution. x y z f ( x , y , z ) 1 1 1 0.05 1 1
1 answer:
Answer:
Determine the conditional probability distribution of X given that Y = 1 and Z = 2. Round your answers to two decimal places (e.g. 98.76).
answer:
Given that Y = 1 : 2/5
Given that Z = 2 : 3/5
Step-by-step explanation:
The conditional probability distribution of X F x | yz^( x )
Given that Y = 1
F x | yz . ( x | yz ) = 2/5
Given that z = 2
= 3/5
attached below is the detailed solution
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Answer:
Step-by-step explanation:
To do this, we must use the unit circle. At the angle the coordinate pair is (
,
) and the hypotenuse is 1
Now that we know these we can start using the trig functions
sin = y
cos = x
tan =
And the other functions would be the reciprocal of these
csc =
sec =
cot =
This would mean that
sinx =
cosx =
tanx = or
if you're supposed to rationalize your denominators
cscx = 2
secx = or
cot =