Suppose the random variables X, Y, and Z have the following joint probability distribution. x y z f ( x , y , z ) 1 1 1 0.05 1 1
1 answer:
Answer:
Determine the conditional probability distribution of X given that Y = 1 and Z = 2. Round your answers to two decimal places (e.g. 98.76).
answer:
Given that Y = 1 : 2/5
Given that Z = 2 : 3/5
Step-by-step explanation:
The conditional probability distribution of X F x | yz^( x )
Given that Y = 1
F x | yz . ( x | yz ) = 2/5
Given that z = 2
= 3/5
attached below is the detailed solution
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Answer:
is a polynomial of type binomial and has a degree 6.
Step-by-step explanation:
Given the polynomial expression
Group like terms
Add similar elements: -8c-8c-9c=-25c
Thus, the polynomial is in two variables and contains two, unlike terms. Therefore, it is a 'binomial' with two, unlike terms.
Each term has a degree equal to the sum of the exponents on the variables.
The degree of the polynomial is the greatest of those.
25c has a degree 1
has a degree 6. (adding the exponents of two variables 'c' and 'd').
Thus,
is a polynomial of type binomial and has a degree 6.