Answer:
1.16 moles CO₂
Explanation:
To find the moles of CO₂, you need to (1) convert grams C₈H₁₈ to moles (via the molar mass) and then (2) convert moles C₈H₁₈ to moles CO₂ (via the mole-to-mole ratio from equation coefficients). It is important that the conversions/ratios are arranged in a way that allows for the cancellation of units. The final answer should have 3 significant figures like the given value.
Molar Mass (C₈H₁₈): 8(12.011 g/mol) + 18(1.008 g/mol)
Molar Mass (C₈H₁₈): 114.232 g/mol
2 C₈H₁₈ + 25 O₂ -----> 16 CO₂ + 18 H₂O
^ ^
16.6 g C₈H₁₈ 1 mole 16 moles CO₂
-------------------- x ----------------- x ------------------------- = 1.16 moles CO₂
114.232 g 2 moles C₈H₁₈
Answer:
Conserved.
Explanation:
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
The law of conservation of momentum states that the total linear momentum of any closed system would always remain constant with respect to time.
This ultimately implies that, the law of conservation of momentum states that if objects exert forces only on each other, their total momentum is conserved.
Answer:
- <em>Alkali metals react with water to produce </em><u>hydroxide and hydrogen gas</u><u>.</u>
Explanation:
That is a chemical property of <em>alkali metals</em>: they are highly reactive and <em>react </em>vigorously <em>with water</em> to produce the correspondant hydroxide and hydrogen gas.
These are some of those reactions:
- 2Li (s) + 2H₂O (l) → 2LiOH (aq) + H₂(g) ↑
- 2Na (s) + 2H₂O (l) → 2NaOH (aq) + H₂(g) ↑
- 2K (s) + 2H₂O (l) → 2KOH (aq) + H₂(g) ↑
The alkali metals are the elements of group 1 of the periodic table: Li, Na, K, Rb, Cs, and Fr. They have one valence electron which may lose easily to form an ion with charge +1.
PbCl2--->Pb2+ + 2Cl-
The mass of PbCl2 is =mass of the beaker+Pbcl2 minus mass of the beaker
that is 62.19-57.77g= 4.42grams
moles of PbCl2= 4.42g/278g/m0l = 0.0159moles
concentration of (Pb2+)
since mole ratio of PbCl2 to Pb2+ is 1:1 therefore the moles of Pb2+ is also 0.0159moles
concentration =0.0159/100 x1000=0.159M
concentration of CI- is two time that of Pb2+ from the equation above therefore concentration of Cl- = 0.159 x2 =0.318M
