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kenny6666 [7]
3 years ago
7

A barometer can track the activity of storms at different altitudes. true of false

Chemistry
2 answers:
Bogdan [553]3 years ago
8 0
Its all the way round true 99.9% sure because they launch baometers up in the air and it reflects off of the satalght

Mazyrski [523]3 years ago
7 0

The answer is false i just took the quiz on edg.


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12. The vapor pressure of water at 90°C is 0.692 atm. What is the vapor pressure (in atm) of a solution made by dissolving 3.68
luda_lava [24]

Answer : The vapor pressure (in atm) of a solution is, 0.679 atm

Explanation : Given,

Mass of H_2O = 1.00 kg = 1000 g

Moles of CsF = 3.68 mole

Molar mass of H_2O = 18 g/mole

Vapor pressure of water = 0.692 atm

First we have to calculate the moles of H_2O.

\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{1000g}{18g/mole}=55.55mole

Now we have to calculate the mole fraction of H_2O

\text{Mole fraction of }H_2O=\frac{\text{Moles of }H_2O}{\text{Moles of }H_2O+\text{Moles of }CsF}=\frac{55.55}{55.55+3.68}=0.938

Now we have to partial pressure of solution.

According to the Raoult's law,

P_{Solution}=X_{H_2O}\times P^o_{H_2O}

where,

P_{Solution} = vapor pressure of solution

P^o_{H_2O} = vapor pressure of water = 0.692 atm

X_{H_2O} = mole fraction of water = 0.938

P_{Solution}=X_{H_2O}\times P^o_{H_2O}

P_{Solution}=0.938\times 0.692atm

P_{Solution}=0.649atm

Therefore, the vapor pressure (in atm) of a solution is, 0.679 atm

5 0
2 years ago
How many grams of sodium chloride are required to make a 1.0 L solution with a concentration of 3.5 M?
Alex777 [14]

A 1 molar solution is the molecular weight in grams in 1 litre of water, so a 3.5 molar solution would be 58.44g multiplied by 3.5, which is 204.54g in 1L

5 0
3 years ago
In order for substances to dissolve in water, the substances should be bonded by: ionic bonds only covalent bonds only either io
SashulF [63]
I think that it would be <span>either ionic bonds or covalent bonds</span>
5 0
3 years ago
The diagram below shows the main parts of the respiratory system.
Tems11 [23]

Answer:

pharynx > larynx>trachea> bronchi>alveoli   (so B)

Explanation:

nasal cavities (or oral cavity) > pharynx > trachea > primary bronchi (right & left) > secondary bronchi > tertiary bronchi > bronchioles > alveoli (site of gas exchange)

8 0
2 years ago
An evaluation of R was performed, following the procedure described in this module. The barometric pressure was 736 torr, the te
Misha Larkins [42]

mass of mg = 0.035g

calculated R value is less

percentage error = 71.91%


6 0
3 years ago
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