All categories

3 years ago

Help asap! if u answer correct Ill give brainliest!!

Chemistry

2 answers:

SpyIntel [72]3 years ago

7 0

Answer:

I believe it means The universe will exploder or The universe is expanding

Explanation:

Marina86 [1]3 years ago

5 0

Answer:

D. The universe will explode

Explanation:

Sorry if im wrong! Have a great day/night/ afternoon!!

You might be interested in

What characteristics do atoms of manganese- 55, iron-56, and nickel-58 have in common?

Juli2301 [7.4K]

Answer:

same number of neutrons

Explanation:

5 0

3 years ago

Help? Will mark as brainlist!!

DIA [1.3K]

Answer:

1. 4.75

2. 5.50

Explanation:

7 0

3 years ago

What is the volume of a box that has a length of 5 cm a width of 7 cm and a height of 9 cm

yKpoI14uk [10]

Answer:

Answer is 315

Explanation:

9*5*7=315

3 0

4 years ago

Is acid rain exothermic or endothermic?

trasher [3.6K]

Answer:

in the presence of water, a strong acid will dissociate quickly and release heat, so it is an exothermic reaction.

Explanation:

7 0

3 years ago

What is the conecntration of Fe3 and the concentration of No3- present in the solution that result when 30.0 ml of 1.75M Fe(No3)

zvonat [6]

Answer:

$[Fe^{+3}]=0.700 M$

$[NO_{3}^{-}]=2.10 M$

Explanation:

Here, a solution of Fe(NO₃)₃ is diluted, as the total volume of the solution has increased. The formula for dilution of the compound is mathematically expressed as:

$C_{1}. V_{1}= C_{2}.V_{2}$

Here, C and V are the concentration and volume respectively. The numbers at the subscript denote the initial and final values. The concentration of Fe(NO₃)₃ is 1.75 M. As ferric nitrate dissociates completely in water, the initial concentration of ferric is also 1.75 M.

Solving for [Fe],

$[Fe^{+3}]=\frac{C_{1}.V_{1}}{V_{2} }$

$[Fe^{+3}]=\frac{(1.75).(30.0)}{45.0+30.0 }$

$[Fe^{+3}]=0.700 M$

For [NO₃⁻],

There are three moles of nitrate is 1 mole of Fe(NO₃)₃. This means that the initial concentration of nitrate ions will be three times the concentration of ferric nitrate i.e., it will be 5.25 M.

$[NO_{3}^{-}]=\frac{C_{1}.V_{1}}{V_{2} }$

$[NO_{3}^{-}]=\frac{(5.25)(30.0)}{30.0+45.0 }$

$[NO_{3}^{-}]=2.10 M$

7 0

3 years ago