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Ne4ueva [31]
3 years ago
15

How many grams of Mg are needed to produce 224 g of MgO in the complete reaction of Mg

Chemistry
1 answer:
zmey [24]3 years ago
7 0

Answer:

134.4 g of Mg

Explanation:

reaction:

2Mg + O2 ➡️ 2MgO

1) find the mol of MgO

mol = mass / molar mass

mass = 224 g

molar mass = 24+16 = 40

mol = 224 / 40

= 5.6 moles

2 mol = 5.6 moles

2) find the mass of Mg

mass = mol × molar mass

mol = 5.6

molar mass = 24

mass = 5.6 × 24

= 134.4 g

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PLEASE ANSWER, I WILL GIVE BRAINLIEST AND THANKS!
zheka24 [161]

Answer:

Mass  = 8 g

Explanation:

Given data:

Mass of MgO formed  = 20 g

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Solution:

Chemical equation:

2Mg + O₂     →    2MgO

Number of moles of MgO:

Number of moles = mass/molar mass

Number of moles = 20 g/ 40 g/mol

Number of moles = 0.5 mol

Now we will compare the moles of MgO and O₂ from balance chemical equation:

                     MgO         :            O₂

                        2            :            1

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Mass of oxygen required:

Mass = number of moles × molar mass

Molar mass of O₂  is 32 g/mol

Mass = 0.25 mol × 32 g/mol

Mass = 8 g

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